 | Benjamin Greenleaf - Algebra - 1879 - 322 pages
...obtain 2 %/a. Hence the following RULE. Seduce the radical parts, if necessary, to a common index; then divide the coefficient of the dividend by the coefficient of the divisor, and the radical part of the dividend by that of the divisor, and prefix the first quotient to the last... | |
 | Algebra - 1888 - 492 pages
...by The division can also be performed without reducing the quantities to their simplest form. Thus, Rule. — Divide the co-efficient of the dividend by the co-efficient of the divisor for< the co-efficient of the quotient. EXERCISES. . Divide: 1. л/Ш) by 2л/8. 5. 24л/2 by 2л/8.... | |
 | Edward Brooks - Algebra - 1888 - 344 pages
...principle above ; hence the entire quotient is — 6j/2as Sy'Sx, which, reduced, equals 6\/2x. Rule. — I. Divide the coefficient of the dividend by the coefficient of the divisor, and the radical part of the dividend by the radical part of the divinar . IL Annex the latter quotient... | |
 | Edward Brooks - Algebra - 1888 - 190 pages
...dividing gOa56 -s- 5os - 4a26 a5 by a3, we have a* (Prin. 2). Hence the quotient is 4a26. Rule. — I. Divide the coefficient of the dividend by the coefficient of the divisor for the coefficient of the quotient. II. Write the letters of the dividend in the quotient, giving... | |
 | John Bernard Clarke - Algebra - 1889 - 566 pages
...corresponding quantity in the divisor. As the letters employed may represent any quantities whatever, we deduce the following RULE. — Divide the coefficient of the dividend by the coefficient of the divisor. To the result, as a coefficient, annex the radical sign, with unchanged index, placing under it the... | |
 | George Albert Wentworth - Algebra - 1891 - 380 pages
...aaaaaa aaaa = aa =a' = a aaaa = aaa = a = a 79. To divide one monomial by another, therefore, we have the following rule : Divide the coefficient of the dividend by the coefficient of the divisor (observing the law of signs), and subtract the index of any letter in the divisor from the ir dex of... | |
 | Charles Davies - Algebra - 1891 - 306 pages
...Division of Radicals. 147. Radical quantities are divided like other algebraic quantities. Hence we have the following rule : — Divide the coefficient of the dividend by the coefficient of the divisor, for a new coefficient. Divide the radical part of the dividend by the radical part of the divisor,... | |
 | William James Milne - Algebra - 1894 - 214 pages
...term must be divided separately. RULE. Divide each term of the dividend by the divisor as follows : Divide the coefficient of the dividend by the coefficient of the divisor. To this quotient annex each literal factor of that term of the dividend with an exponent equal to the... | |
 | William James Milne - Algebra - 1894 - 216 pages
...term must be divided separately. KULE. Divide each term of the dividend by the divisor as follows : Divide the coefficient of the dividend by the coefficient of the divisor. To this quotient annex each literal factor of that term of the dividend with an exponent equal to the... | |
 | Emerson Elbridge White - Algebra - 1896 - 418 pages
...— 120а4Лв by - Загйг5. 15. 343™«^^ by — 49mn2p/124. To divide one monomial by another, Divide the coefficient of the dividend by the coefficient of the divisor, prefixing the sign + if the signs are alike, and the sign — if the signs are unlike. Annex to this... | |
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Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and strike out the letters of the divisor from the dividend. 
