 | George Willson - Arithmetic - 1836 - 202 pages
...mentioned in it.* * It is often better to reduce the lower denominations to the decimal of the highest. 3. Multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in that denomination which the third term was left in. In arranging... | |
 | Abel Flint - Geometry - 1837 - 338 pages
...is calculated accordingly. GENERAL ROLE. 1. State the question in every case, as already taught : 2. Multiply the second and third terms together, and divide the product by the first. The manner of taking natural sines and tangents from the tables, is the same as for logarithmic sines and... | |
 | Peirpont Edward Bates Botham - Arithmetic - 1837 - 252 pages
...question. The first and third terms must be of one name. The second term of -divers denominations. Multiply the second and third terms together, and divide the product by the first term ; the quotient thence arising will be the Answer. OBS. This rule is founded on the obvious principle,... | |
 | Luther Ainsworth - Arithmetic - 1837 - 306 pages
...direct, multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term or answer, in the same denomination you left the second term in, arid must be brought to the denomination required by the question. Q.... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pages
...When the terms are stated and reduced, how do you proceed in order to find a fourth proportional? I multiply the second and third terms together, and divide the product by the first, the quotient is the answer. In what name are the product of the second and third terms, the quotient, and the remainder... | |
 | Thomas Holliday - Surveying - 1838 - 404 pages
...3.—By arithmetical computation. Having stated the question according to the proper rule or case, multiply the second and third terms together and divide the product by the first, and the quotient will be the fourth term required for the natural number. But in working by logarithms,... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...mentioned in it.* * It is often better to reduce the lower denominations to tha daeimil «f the highest 3. Multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in that denomination which the third term was bft in. In arranging... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...denomination, reduce both to the lowest in either, and the third to its lowest denomination mentioned. Multiply the second and third terms together, and...the product by the first : the quotient will be the answer to the question, in the same denomination you left the third term in. Proof. — Invert the... | |
 | Joseph Stockton - Arithmetic - 1839 - 218 pages
...the first, but if less place the greater for the first term, and the remaining one for the second. Multiply the second and third terms together, and...the product by the first ; the quotient will be the answer required. EXAMPLES. 1. If 30 horses plow 12 acres, how many will 40 horses plow in the same... | |
 | Joseph Stockton - Arithmetic - 1839 - 216 pages
...the middle term (if compound) to its lowest, and proceed according to the following -*» RULE. \ « Multiply the second and third terms together, and divide the product by the first; the quotient wilfbe the fourth term, or answer, in the same name with the PROOF. Invert the question, making the... | |
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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 
