 | Alexander Ingram - 1881 - 192 pages
...times, may be equitably paid at once. RULE. Multiply each debt by the time which must elapse before it is due; then divide the sum of the products by the sum of the debts for the equated time nearly. Ex. Find the equated time, when £50 due in 70 days, £60 due in... | |
 | Alexander Ingram - 1883 - 190 pages
...times, may be equitably paid at once. RULE. Multiply each debt by the time which must elapse before it is due ; then divide the sum of the products by the sum of the debts for the equated time nearly. Ex. Find the equated time, when £50 due in 70 days, £60 due in... | |
 | Daniel W. Fish - Arithmetic - 1883 - 364 pages
...due in 4 mo., and $1000 due in 6 mo. RULE. — 1. Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient is the average term of credit. 2. To find the equated time of payment.— Add the average... | |
 | James Gray - Arithmetic - 1883 - 154 pages
...which a debt due at different times may be discharged at once, without disadvantage to either party. RULE. Multiply each payment by the time at which it is due ; divide the sum of the products by the amount of the debt : the quotient is the time required. 1.... | |
 | Joseph Ray - Arithmetic - 1885 - 358 pages
...COMMON RULE FOR EQUATION OP PAYMENTS. Multiply each payment by the time to elapse till it becomes due; divide the sum of the products by the sum of the payments ; the quotient will be the equated time. When one of the payments is due on the day from which the... | |
 | M. P. Caldwell - Arithmetic - 1883 - 198 pages
...EQUATION OF PAYMENTS. different times, may be made at once, without loss t6 either party. R m .K. — Multiply each payment by the time at which it is due;...of the products by the sum of the payments, and the quotient will be the mean lime. EXAMPLES. i. John owes James $300, of which $50 is due in 2 months,... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...of 3560 months, which is 4J| months. RULE. — I. Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit. II. Add the average term of credit to the date at... | |
 | Edward Sylvester Ellis - Arithmetic - 1889 - 370 pages
...time, when the terms of credit begin on the same date, — Multiply each debt by its term of credit and divide the sum of the products by the sum of the payments. NOTE. — Whenever cents appear in the debts, they should be rejected if less than 50 and counted as... | |
 | John Homer French - Arithmetic - 1889 - 512 pages
...credit: — PBODUCT METHOD. — Multiply each term of credit by the number expressing the payment, and divide the sum of the products by the sum of the payments. Or, IMTEKEST METHOD. — Find the interest of each debt for its term of credit, and divide the sum... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...months on $ 30, smce 30 x 6 = 180 x 1. RULE.—I. Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit. II. Add the average term of credit to the date at... | |
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RULE. Multiply each payment by the time at which it is due, then divide the sum of the products by the sum of the payments, and the quotient will be the answer. 
