| John Playfair - Circle-squaring - 1819 - 333 pages
...to all the angles of the figure, together with four right angles, that is, the angles of the figure **are equal to twice as many right angles as the figure has sides,** wanting four. COR. 2. All the exterior angles of any rectilineal figure are tegether equal to four... | |
| John Playfair - 1819 - 317 pages
...from a point F within the figure to each of its angles. And, by the preceding proposition, all the **angles of these triangles are equal to twice as many right angles as** there are triangles, that is, as there are sides of the figure ; and the same angles are equal to the... | |
| Euclid - 1822 - 179 pages
...equal (i)Prop. 13. to two right angles (1), therefore all the external angles, with all the internal, **are equal to twice as many right angles as the figure has sides** ; but the internal angles, together with four right angles, are equal to twice as many rightangles... | |
| Charles Hutton - Mathematics - 1822
...triangles, is equal to two right angles (th. 17) ; therefore the sum of the angles of all the triangles is **equal to twice as many right angles as the figure has sides.** But the sum of all the angles about the point p, which are so / many of the angles of the triangles,... | |
| Edward Riddle - Navigation - 1824 - 551 pages
...twice as many right angles as the figure has sides ; or the interior angles of the figure, themselves, **are equal to twice as many right angles as the figure has sides,** wanting four right angles. QED Cor. 1. All the interior angles of any quadrilateral figure are together... | |
| Peter Nicholson - Mathematics - 1825 - 372 pages
...lines from a point F within the figure to each of its angles. And, by the preceding proposition all the **angles of these triangles are equal to twice as many right angles as** there are triangles, that is, as there are sides of the figure, and the same angles are equal to the... | |
| George Lees - 1826
...lines from a point F within the figure to each of its angles. And, by the preceding theorem, all the **angles of these triangles are equal to twice as many right angles as** there are triangles, that is, as there are sides of the figure ; and the same angles are equal to the... | |
| Robert Simson - Trigonometry - 1827 - 513 pages
...from a point F, within the figure to each of its angles. And, by the preceding proposition, all the **angles of these triangles are equal to twice as many right angles as** there are triangles, that is, as there are sides of the figure : and the same angles are equal to the... | |
| John Radford Young - Euclid's Elements - 1827 - 208 pages
...in each triangle amounts to two right angles, therefore the angles of all the triangles are together **equal to twice as many right angles as the figure has sides,** that is to say, the sum of the angles of the polygon, together with those about the point within it,... | |
| Euclid, Dionysius Lardner - Euclid's Elements - 1828 - 324 pages
...COR. 10. — All the internal angles of any rectilinear figure ABCDE, together with four right angles, **are equal to twice as many right angles as the figure has sides.** Take any point F within the figure, and draw the right, lines FA, FB, FC, FD, and F E. There are formed... | |
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