Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. A System of Arithmetic - Page 159by Samuel Webber - 1812 - 248 pagesFull view - About this book
| Horatio Nelson Robinson - 1888
...will be the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
| Horatio Nelson Robinson - Arithmetic - 1892 - 416 pages
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. To the last complete divisor add the last figure of the root, and to the sum annex one cipher, for... | |
| Frank Eugene Kidder - Architecture - 1892 - 911 pages
...the divisor, multiply this final divisor by the number in the quotient just found, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend,** and proceed as before. 1f it should be found that the trial divisor cannot be contained in the dividend,... | |
| Horatio Nelson Robinson - Arithmetic - 1892 - 416 pages
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. To the last complete divisor add the last figure of the root, and to the sum annex one cipher, for... | |
| Frank Eugene Kidder - Architecture - 1892 - 911 pages
...left-hand period, and place its root in the quotient ; subtract the said square from the left-hand period, **and to the remainder bring down the next period for a new dividend.** 3d, Double the root already found, and annex one cipher for a trial divisor, see how many times it... | |
| Oscar F. Williams - Arithmetic - 1894 - 307 pages
...right of the divisor; multiply the divisor thus formed by the new root figure, subtract the result **from the dividend, and to the remainder bring down the next period,** and so proceed till the last period has been brought down, considering the entire root already found... | |
| Horatio Nelson Robinson - Arithmetic - 1895 - 506 pages
...a complete divisor ; multiply the complete divisor by the trial term in the root, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. To the last complete divisor add the last term of the root, and to the sum annex one cipher, for... | |
| William Allen Sylvester - Architecture, Domestic - 1896 - 254 pages
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the **product from the dividend ; and to the remainder bring down the next period for a new dividend.** o. To the last complete divisor add the last figure of the root, and to the sum annex one cipher for... | |
| Joseph Ray - Arithmetic - 1903 - 320 pages
...of the trial divisor. 4. Multiply the complete divisor by the last figure of the root; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** 5. Double the whole root found, for a new trial divisor, and continue the operation in the same manner... | |
| Calvin Franklin Swingle, Frederick John Prior - Air-brakes - 1906
...the dividend, and it will be the second figure of the root. From the dividend subtract the product, **and to the remainder bring down the next period for a new dividend.** Double the figures in the quotient for a divisor, and continue the operation as above till all the... | |
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