Books Books Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. A System of Arithmetic - Page 159
by Samuel Webber - 1812 - 248 pages ## The Progressive Higher Arithmetic: For Schools, Academies, and Mercantile ...

Horatio Nelson Robinson - 1875 - 446 pages
...for a complete divisor ; multiply the complete divisor by the trial figure irt the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor by 2 znd add the product to 10 times the previous... ## Ray's New Higher Arithmetic: A Revised Edition of the Higher Arithmetic

Joseph Ray - Arithmetic - 1880 - 408 pages
...quotient to the root and to tl,e divisor; then multiply the complete divisor by the quotient, subtract the product from the dividend, and to the remainder bring down the next period as before. 4. Double the root as before, place it on the left as a trial divisor, proceeding as with... ## The System of Calculating Diameter, Circumference, Area, and Squaring the ...

James Morton - Circle-squaring - 1881 - 216 pages
...right hand of the divisor and under the same, and multiply the divisor by this figure. Subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so continue until all the periods are brought down. If any dividend shall be too small to contain... ## The Bryant and Stratton Business Arithmetic

H. Bryant - 1881
...cube of the last rootfgurc, and find their sum, calling it the subtrahend. 7. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before till the required root be found. XOTES. — 1. When any dividend is not... ## The Modern House-carpenters's Companion and Builder's Guide: Being a ...

William Allen Sylvester - Carpentry - 1883 - 210 pages
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend; and to the remainder bring down the next period for a new dividend. 5. To the last complete divisor add the last figure of the root, and to the sum annex one cipher for... ## Mensuration for beginners [With] Answers

William Dodds - 1883
...divisor, aa it now stands, by this last quotient figure, and subtract the product from the dividend. 6°. To the remainder bring down the next period for a new dividend. Then find a new divisor by doubling the figures of the quotient, and proceed as before, till all the... ## An introduction to arithmetic

James Gray - Arithmetic - 1883 - 140 pages
...of these three by the figure last placed in the root, and subtract the product from the dividend. 6. To the remainder bring down the next period for a new dividend, with which proceed as before. Or add up the three last numbers, reckoning the middle one twice in the... ## The Modern House-carpenter's Companion and Builder's Guide: Being a Hand ...

William Allen Sylvester - Carpentry - 1884 - 210 pages
...the complete divisor by the trial HOUSE-CARPENTER'S COMPANION. figure in the root, and subtract the product from the dividend ; and to the remainder bring down the next period for a new dividend. 5. To the last complete divisor add the last figure of the root, and to the sum annex one cipher for... ## The Architect's and Builder's Pocket-book

Frank Eugene Kidder - Architecture - 1886 - 621 pages
...the divisor, multiply this final divisor by the number in the quotient just found, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and proceed as before. If it should be found that the trial divisor cannot be contained in the dividend,... 