Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. A System of Arithmetic - Page 159by Samuel Webber - 1812 - 248 pagesFull view - About this book
| Horatio Nelson Robinson - 1875 - 446 pages
...for a complete divisor ; multiply the complete divisor by the trial figure irt the root, subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. Multiply the last figure of the last complete divisor by 2 znd add the product to 10 times the previous... | |
| Joseph Ray - Arithmetic - 1880 - 408 pages
...quotient to the root and to tl,e divisor; then multiply the complete divisor by the quotient, subtract the **product from the dividend, and to the remainder bring down the next period** as before. 4. Double the root as before, place it on the left as a trial divisor, proceeding as with... | |
| James Morton - Circle-squaring - 1881 - 216 pages
...right hand of the divisor and under the same, and multiply the divisor by this figure. Subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend,** and so continue until all the periods are brought down. If any dividend shall be too small to contain... | |
| H. Bryant - 1881
...cube of the last rootfgurc, and find their sum, calling it the subtrahend. 7. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period for a new dividend,** with which proceed as before till the required root be found. XOTES. — 1. When any dividend is not... | |
| William Allen Sylvester - Carpentry - 1883 - 210 pages
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the **product from the dividend; and to the remainder bring down the next period for a new dividend.** 5. To the last complete divisor add the last figure of the root, and to the sum annex one cipher for... | |
| William Dodds - 1883
...divisor, aa it now stands, by this last quotient figure, and subtract the product from the dividend. 6°. **To the remainder bring down the next period for a new dividend.** Then find a new divisor by doubling the figures of the quotient, and proceed as before, till all the... | |
| James Gray - Arithmetic - 1883 - 140 pages
...of these three by the figure last placed in the root, and subtract the product from the dividend. 6. **To the remainder bring down the next period for a new dividend,** with which proceed as before. Or add up the three last numbers, reckoning the middle one twice in the... | |
| William Allen Sylvester - Carpentry - 1884 - 210 pages
...the complete divisor by the trial HOUSE-CARPENTER'S COMPANION. figure in the root, and subtract the **product from the dividend ; and to the remainder bring down the next period for a new dividend.** 5. To the last complete divisor add the last figure of the root, and to the sum annex one cipher for... | |
| Frank Eugene Kidder - Architecture - 1886 - 621 pages
...the divisor, multiply this final divisor by the number in the quotient just found, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend,** and proceed as before. If it should be found that the trial divisor cannot be contained in the dividend,... | |
| M. P. Caldwell - Arithmetic - 1883 - 191 pages
...the true divisor by the last figure placed in the root, and subtract its product from th, dividend. **To the remainder bring down the next period for a new dividend** and proceed as before. CUBE ROOT. NtTE. — If fractions occur, extract the cube root of the numerator... | |
| |