Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. A System of Arithmetic - Page 159by Samuel Webber - 1812 - 248 pagesFull view - About this book
| Horatio Nelson Robinson - Algebra - 1875 - 412 pages
...for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor, with which... | |
| Horatio Nelson Robinson - Algebra - 1875 - 318 pages
...the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. Double the right-hand figure of the last complete divisor for a new divisor, and continue the operation... | |
| Lorenzo Fairbanks - 1875
...the divisor. IV. Multiply the divisor thus obtained by the digit of the root last found: subtract the **product from the dividend, and to the remainder' bring down the next period for a new dividend.** V. Double the part of the root already found, for a new divisor, and proceed as before ; and so on,... | |
| Thomas Henderson - 1876
...the square of the last figure. Multiply the complete divisor by the last root figure, subtract the **product from the dividend, and to the remainder bring down the next period,** if any, or add three cyphers, for a new dividend. To the last complete divisor add the two numbers... | |
| George Augustus Walton - 1876
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend, **To the remainder bring down the next period for a new dividend.** Multiply the square of the terms of the root already found (considtred as (em), ty three for a trial... | |
| Joseph Ray - Arithmetic - 1877 - 336 pages
...the complete divisor. 5. Multiply the complete divisor by the last figure of the root; subtract the **product from the dividend, and to the remainder bring...down the next period for a new dividend. 6. Find a** new trial divisor as before, and continue the operation in the same manner until all the periods are... | |
| Joseph Ray - Arithmetic - 1877 - 336 pages
...divisor. P«c. •» 4. Multiply the complete divisor by the last figure of the root; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** 5. Double the whole root found, for a new trial divisor, and continue the operation in the same manner... | |
| Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1877 - 359 pages
...will be the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the **product from the dividend, and to the remainder bring down the next** jjeriodfor a new dividend. VI. Add the square of the last figure of the root, the last term in column... | |
| Horatio Nelson Robinson - Algebra - 1879 - 324 pages
...the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** V. Double the right-hand figure of the last complete divisor for a new divisor, and continue the operation... | |
| Clement Mackrow - 1879
...the dividend, and it will be the second figure of the root. From the dividend subtract the product, **and to the remainder bring down the next period for a new dividend** ; double the figures in the quotient for a divisor, and continue the operation as above till all the... | |
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