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" Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. "
A System of Arithmetic - Page 159
by Samuel Webber - 1812 - 248 pages
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A Treatise on Algebra

Elias Loomis - Algebra - 1864 - 359 pages
...second figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue...
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A Written Arithmetic, for Common and High Schools: To which is Adapted a ...

George Augustus Walton - Arithmetic - 1864 - 348 pages
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Multiply the square of the terms of the root already found (considered as fens), by three for a trial...
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A Written Arithmetic, for Common and High Schools: To which is Adapted a ...

George Augustus Walton - Arithmetic - 1864 - 348 pages
...true divisor thus obtained by the last term of the root, and subtract this product from the dividend ; to the remainder bring down the next period for a new dividend. Double the terms of the root already found for a new trial divisor, and proceed as before. NOTE I....
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School Arithmetic: Analytical and Practical

Charles Davies - Arithmetic - 1865 - 336 pages
...the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation...
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The parallel arithmetic

W H. Wingate - Arithmetic - 1865 - 121 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take from the dividend, and to the remainder bring down the next period, and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor...
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Primary Elements of Algebra: For Common Schools and Academies

Joseph Ray - Algebra - 1866 - 240 pages
...the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until...
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Elements of Algebra: For Colleges, Schools, and Private Students, Book 2

Joseph Ray - Algebra - 1866 - 406 pages
...the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor, and continue the operation as before, until...
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Ray's Algebra, Part Second: An Analytical Treatise, Designed for ..., Part 2

Joseph Ray - Algebra - 1852 - 396 pages
...complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. Extract the cube root of the following numbers....
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The Engineer's examination made easy

Robert Thomson (of Southampton.) - 1866 - 143 pages
...the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next point for a new dividend, double the last figure set in the divisor and proceed as before to the last...
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The Foreign and Domestic Commercial Calculator; Or, A Complete Library of ...

Ezra S. Winslow - Business mathematics - 1867 - 220 pages
...divisor ; multiply the divisor, thus increased, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by...
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