Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. A System of Arithmetic - Page 159by Samuel Webber - 1812 - 248 pagesFull view - About this book
| Elias Loomis - Algebra - 1864 - 359 pages
...second figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend. 6.** Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
| George Augustus Walton - Arithmetic - 1864 - 348 pages
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. **To the remainder bring down the next period for a new dividend.** Multiply the square of the terms of the root already found (considered as fens), by three for a trial... | |
| George Augustus Walton - Arithmetic - 1864 - 348 pages
...true divisor thus obtained by the last term of the root, and subtract this product from the dividend ; **to the remainder bring down the next period for a new dividend.** Double the terms of the root already found for a new trial divisor, and proceed as before. NOTE I.... | |
| Charles Davies - Arithmetic - 1865 - 336 pages
...the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the **product from the dividend, and to the remainder bring down the next period for a** neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
| W H. Wingate - Arithmetic - 1865 - 121 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take **from the dividend, and to the remainder bring down the next period,** and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
| Joseph Ray - Algebra - 1866 - 240 pages
...the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** 5. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
| Joseph Ray - Algebra - 1866 - 406 pages
...the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend.** 5th. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
| Joseph Ray - Algebra - 1852 - 396 pages
...complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the **product from the dividend, and to the remainder bring down the next period for a new dividend,** and so proceed until all the periods are brought down. Extract the cube root of the following numbers.... | |
| Robert Thomson (of Southampton.) - 1866 - 143 pages
...the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the **product from the dividend, and to the remainder bring down the next** point for a new dividend, double the last figure set in the divisor and proceed as before to the last... | |
| Ezra S. Winslow - Business mathematics - 1867 - 220 pages
...divisor ; multiply the divisor, thus increased, by the last figure in the quotient, and subtract the **product from the dividend, and to the remainder bring down the next period for a** dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by... | |
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