 | Joseph Ray - Algebra - 1866 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Robert Thomson (of Southampton.) - Marine engineers - 1866 - 180 pages
...number : cube this figure placed in the quotient and place its product under the first period, subtract and to the remainder bring down the next period for a dividend. Example 1st. — Extract the cube or third root of 312908547060. 6x6=36 6x3=18x6= 10800 187x7= 1309... | |
 | William Harding Girdlestone - 1867 - 368 pages
...can be subtracted from the lefthand period ; write this as the first figure in the root, subtract its square from the first period, and to the remainder bring down the next period. Double the first figure of the root, place it on the left of the remainder, and using it as a divisor,... | |
 | Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...divisor, thus increased, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by 2, as before,... | |
 | Joseph Ray - Arithmetic - 1857 - 358 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times this divisor... | |
 | Elias Loomis - Algebra - 1868 - 386 pages
...is contained in the left-hand period ; this is the first figure of the required root. Subtract its square from the first period, and to the remainder bring down the second period for a dividend. Bd. Double the root already found for a 'divisor, and find how many times... | |
 | Robert Wallace - 1870 - 164 pages
...the left-hand period, and place its root to the left, as the first figure of the root ; subtract its square from the first period, and to the remainder bring down the next period for a dividend. Divide this new dividend (excluding the right-hand figure) by twice the first figure of the root, and... | |
 | Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...the manner of a quotient in division, for the first figure of the root. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor, and find how often the divisor is contained in the dividend,... | |
 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...and write its root for the first figure in the root ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the first figure of the root, and write it at the left of tJie dividend for a TRIAL DIVISOR;... | |
 | Ezra S. Winslow - Business mathematics - 1872 - 256 pages
...divisor, thus increase^, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by 2, as before,... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
