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" Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. "
Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain and ... - Page 91
by Nathan Daboll - 1813 - 240 pages
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The practical arithmetic

John Darby (teacher of mathematics.) - 1843 - 236 pages
...therein stated; then multiply the first and second terms together, and divide the product by the third, and the quotient will be the answer to the question in the same denomination the second term was left in. Or, by the general rule, given in the Rule of Three Direct. EXAMPLES....
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A manual of arithmetic

George Hutton (arithmetic master, King's coll. sch.) - 1844 - 276 pages
...the quantity reserved for the third term. 5. Lastly, multiply together the second and third terms, and divide their product by the first term ; and the quotient will be the fourth term of the proportion, or answer to the question ; and will be always of the same denomination...
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Introduction to The National Arithmetic: On the Inductive System; Combining ...

Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...lowest denomination mentioned in either, and the third term to the lowest denomination mentioned in it. Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to which the third is reduced. If any thing...
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Introduction to The National Arithmetic, on the Inductive System: Combining ...

Benjamin Greenleaf - Arithmetic - 1844 - 204 pages
...lowest denomination mentioned in either, and the third term to the lowest denomination mentioned in it. Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to tohich the third is reduced. If any thing...
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Elementary and practical Arithmetic on the inductive system, by analysis and ...

Charles WATERHOUSE - Arithmetic - 1844 - 228 pages
...second term, and the other for the first Multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer. If the first and second terras be compound numbers, reduce those terms to the lowest denomination contained...
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A system of practical arithmetic

William Lane (of Worthing.) - 1845 - 138 pages
...lowest denomination it contains. Then multiply the second and third terms together, and divide the product by the first term, and the quotient will be...the answer to the question, in the same denomination that the third term was reduced to ; which must be brought again, if necessary, to the highest denomination...
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Watson's Tutor's assistant; or, Complete school arithmetic

William Watson (of Beverley.) - 1845 - 188 pages
...mentioned in it. 3. — Multiply the second and third terms together and divide the product by the first, the quotient will be the answer to the question in the same name the second term was brought into. The method of proof is by inverting the question. EXAMPLES....
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Arithmetic, Its Principles and Practice

James W. Kavanagh - 1846 - 304 pages
...after the third, and the marks (: :) for equality between the means. Having now arranged the terms, we multiply the second and third terms together, and divide their product by the first, the resulting quotient, 98, being the reiuired answer in shillings. The pupil is to recollect that,...
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The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - Arithmetic - 1846 - 370 pages
...proportion to be found, .and make the third statement in the same manner as the second was made. III. Then multiply the second and third terms together, and divide their product by the product of the first terms, and the quotient will be the answer sought. EXAMPLES. Let us first resolve...
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Pantology

Roswell Park - Best books - 1847 - 626 pages
...placed last of those two, and the greater of them will be the first. The question being thus stated, multiply the second and third terms together, and divide their product by the first; and the quotient will be the fourth term, or answer sought. A Compound Proportion, including the solution...
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