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" It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. "
Key to Davies' Bourdon: With Many Additional Examples, Illustrating the ... - Page 92
by Charles Davies - 1856 - 205 pages
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A University Algebra ...

Edward Olney - Algebra - 1873 - 354 pages
...overtake the first ? 4. Divide the number 48 into two such parts that their product may be 432. 5. Divide the number 24 into two such parts that their product may be equal to 35 times their difierence. 7. The fore wheel of a coach makes 6 revolutions more than the hind wheel in going 120...
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New Elementary Algebra: Containing the Rudiments of the Science for Schools ...

Horatio Nelson Robinson - Algebra - 1874 - 340 pages
...two such parts, that the sum of the squares of those parts shall be b. Am. £(a± v^¿) — a2). 4. It is required to divide the number 24 into two such...product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the sum of their cubes 152 ; what are the numbers...
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A University Algebra

Edward Olney - 1878 - 360 pages
...number 48 into two such parts that their product may be 432. 5. Divide the number 24 into two Buch parts that their product may be equal to 35 times their difference. 7. The fore wheel of a coach makes 6 revolutions more than the hind wheel in going 120 yards; but,...
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Key to Davies' Bourdon: With Many Additional Examples, Illustrating the ...

Charles Davies - Algebra - 1879 - 288 pages
...2304, or x* - 100ж = - 2304. whence, by the rule, ж = 50±уТ96~=50 ± 14; hence, x = 64, x = 36, and у = 36, у = 64. 11. It is required to divide...denote the parts. From the conditions of the problem. ж + у = 24 . . . (1) *y = S5(xy) . . . (2); substituting in (2) the value, у = 24 — x, 24ж -...
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A University Algebra

Edward Olney - Algebra - 1880 - 354 pages
...will come together ? 4. Divide the number 48 into two such parts that their product may be 432. 5. Divide the number 24 into two such parts that their...product may be equal to 35 times their difference. C. For a journey of 108 miles, G hours less Avould have sufficed, had the traveller gone 3 miles an...
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A University Algebra: Comprising a Compendious, Yet Complete and Thorough ...

Edward Olney - Algebra - 1882 - 358 pages
...will come together ? 4. Divide the number 48 into two such parts that their product ymay be 432. 5. Divide the number 24 into two such parts that their...product may be equal to 35 times their difference. 7. The fore wheel of a coach makes 6 revolutions more than the hind wheel in going 120 yards ; but,...
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Algebra Adapted to the Requirements of the First Stage of the ..., Part 2

Edward Mann Langley, S. R. N. Bradly - Algebra - 1903 - 280 pages
...person £5 a piece more than A. Now, how many persons were relieved by A and В respectively ? (26) It is required to divide the number 24 into two such...product may be equal to 35 times their difference. (27) A and В set off at the same time to a place distant 300 miles. A travels at the rate of one mile...
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New Elementary Algebra Embracing the First Principles of the Science

Charles Davies - Algebra - 1891 - 312 pages
...13. Divide 100 into two such parts that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such...product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the sum of their cubes is 152. What are the numbers...
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