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In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side subtending the obtuse angle is greater than the squares on the sides containing the obtuse angle, by twice the...
Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ... - Page 96
by Robert Potts - 1860 - 361 pages

## A Text-book of Geometrical Deductions: Corresponding to Euclid, book ..., Book 2

James Blaikie - 1892
...obtuse-angled triangle, the square on the side subtending the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle by twice the rectangle contained by either of these sides, and the produced part of it intercepted between the perpendicular let fall on...

## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclid, Robert Simson - Geometry - 1892 - 518 pages
...obtuse.angled triangle the square on the side opposite the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle by twice the rectangle contained by either of those sides, and the projection of the other side upon it. Prop. 13 may be written AC2=AB2+BC2-2CB.BD,...

## Euclid's Elements of Geometry, Books 1-6

Henry Martyn Taylor - 1893 - 504 pages
...square on the part produced. PROPOSITION 12. In an obtuse-angled triangle, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side opposite the obtuse angle is greater than the sum of the srjuares on tlte other sides, by twice tite...

## Examination Papers for Science Schools and Classes

...quantity to each of its terms. B. 27. Show that in an obtuse angled triangle, if a perpendicular be drawn from either of the acute angles to the opposite side...angle, by twice the rectangle contained by the side on which, when produced, the perpendicular falls, and the straight line intercepted without the triangle,...

## Euclid's Elements of Geometry, Books 1-6; Book 11

Henry Martyn Taylor - 1895 - 657 pages
...square on the part produced. PROPOSITION 12. In an obtuse-angled triangle, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side opposite the obtuse angle is greater than the sum of tJie squares on the other sides, by twice the...

## Science Examination Papers

...from one of the acute angles of an obtuse-angled triangle to the opposite side produced ; show that the square on the side subtending the obtuse angle...angle by twice the rectangle contained by the side on which, when produced, the perpendicular falls, and the straight line intercepted between the perpendicular...

## Report of the Committee of Council on Education in Scotland...[without Appendix]

Education - 1899
...the problem may have a solution. 3. In obtuse-angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite side produced,...side subtending the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle, bv twice the rectangle contained by the...

## A Text-book of Euclid's Elements for the Use of Schools, Books I.-IV., Book 1

Henry Sinclair Hall, Frederick Haller Stevens - Euclid's Elements - 1900 - 304 pages
...medial section at A. PROPOSITION 12. THEOREM. In an obtuse.angled triangle, if a perpendicular is drawn from either of the acute angles to the opposite side...side subtending the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle, by twice the rectangle contained by the...

## Report of the Committee of Council on Education in Scotland...[without Appendix]

Education - 1900
...AC, and CN ie drawn perpendicular to AB, show that BC1 = 2AB . BN. 7. G. In an obtuse-angled triangle the square on the side subtending the obtuse angle is greater than the sum of the squares on the other two sides by twice the rectangle contained by either of these sides,...

## Annual Report of the Commissioners ..., Volume 67

1901
...In an obtuse-angled triangle, the square on the side subtending the obtuse angle exceeds the sum of the squares on the sides containing the obtuse angle, by twice the rectangle contained by either of them, and its continuation to meet a perpendicular on it from the opposite angle. 4. Prove...