 | Thomas Holliday - Surveying - 1838 - 404 pages
...it stand upon ? PROBLEM IV. Answer, 4134.49 feet. TO FIND THE AREA OF A RECTANGLE. Rule.—Multiply the length by the breadth, and the product will be the area. Note. Buildings, streets, drains, new roads, &c., are in general rectangles; and artificers generally... | |
 | Nathan Daboll - 1839 - 220 pages
...rods to acres.] Ans. 26 acres 1 r. 25 rods. PROB. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden which is 126 feet long and 65... | |
 | Joseph Stockton - Arithmetic - 1839 - 216 pages
...32J perches. 3<2. To find the content of an oblong square piece of ground, called a parallelogram. RULE. Multiply the length by the breadth, and the product will be the answer. EXAMPLE. i 1. There is an oblong square piece of ground, A, B, C, D, the longest sides of which... | |
 | Robert Goodacre - 1839 - 320 pages
...Example 1 29 Miscellaneous Questions. CASE 1. — To find the area of any rectangular superficies. Multiply the length by the breadth, and the product will be the area in square measure. In measuring superficies, in which the dimensions vary, it is common to take the... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...given, to find the area ; or the area and one side given, to find the length of the other aide. RULE. 1. Multiply the length by the breadth, and the product will be the area. 2. Divide the area by one of the sides, and the quotient will be the adjacent side. Examples. 1. What... | |
 | Charles Davies - Geometrical drawing - 1840 - 264 pages
...the more accurate methods by means of figures. PROBLEM I. 2. To find the area of a board or plank. RULE. Multiply the length by the breadth, and the product •will be the content required. Of Timber Measure. NOTE. — 3. If the board is tapering, add the breadths of the... | |
 | Daniel Adams - Arithmetic - 1848 - 316 pages
...multiply the number of squares in one row by the number of rows ; 5X3=15 square rods, Ans. Hence the RULE. Multiply the length by the breadth, and the product will be the square contents. NOTE. — Three times a line 5 rods long is a line 15 rods long. Hence the pupil must... | |
 | William Ruger - Arithmetic - 1841 - 268 pages
...measuring 40 rods on each side ? Ans. 10 acres. 24 feet. To find the area of a parallelogram, or long square. RULE. — Multiply the length by the breadth, and the product will ea, or superficial content, in the same name with the length be the area, of the sides. 100 rods. EXAMPLES.... | |
 | Nathan Daboll - Arithmetic - 1843 - 254 pages
...rods to acres.] Ans. 26 acres I r. 25 rods. PROB. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden which is 126 feet long and 65... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...MENSURATION OF SURFACES. PROBLEM 1. — To find the area of a square, rectangle, parallelogram, SfC. * RULE. — Multiply the length by the breadth, and the product will be the area, or multiply half the sum of the parallel sides by their perpendicular distance. EXAMPLES. 1. What is the... | |
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To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. 
