| Elias Loomis - Algebra - 1858 - 394 pages
...figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 472 pages
...for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the product annex two ciphers for... | |
| Charles Haynes Haswell - Measurement - 1858 - 350 pages
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor is contained... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...represent? What is the rule for extracting the cube root ? Subtract the subtrahend from the dicidend, and to the remainder bring down the next period for a new dicidend, with which proceed at before; and so on, till the whole is completed. NOTE 1. — In separating... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
| Charles Guilford Burnham - 1859 - 338 pages
...contained in the diwdend, and place the result in the quotient, for the second figure of the root. VI. Multiply the triple square by the last quotient figure,...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? ,... | |
| Benjamin Greenleaf - Arithmetic - 1859 - 334 pages
...its contents ? What part of Fig. 4 does it represent ? What is the rule for extracting the cube root? Subtract the subtrahend from the dividend, and to...next period for a new dividend, with which proceed ai before ; and so on, till the whole is completed. NOTE 1. — In separating the given number into... | |
| Horatio Nelson Robinson - Arithmetic - 1859 - 352 pages
...the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
| Benjamin Greenleaf - Arithmetic - 1860 - 324 pages
...call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder faing down the next period for a new dividend, with which proceed as before; and so on, till the whole is completed. NOTE 1. — In separating the given number into periods, when the num ber of the figures... | |
| James Bates Thomson - Arithmetic - 1860 - 440 pages
...; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c., as before, and thus continue... | |
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