 | Pliny Earle Chase - Arithmetic - 1848 - 240 pages
...Then the difference of the extremes 24, must be 8 times the common difference, which is therefore 3. RULE. \ Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. This difference repeatedly added to the less,... | |
 | Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 249 pages
...last day ? Ans. 33 miles. CASE n. • ' The first term, last term, and number of terms given, to f,nd the common difference. RULE. Divide the difference...1, and the quotient will be the common difference. EXAMPLES. 1. A man bought 17 yards of cloth in arithmetical progression. For the first yard he gave... | |
 | James Bates Thomson - 1849 - 438 pages
...12 hours? 604. To find the common difference, when the extremes and the number of terms are given. Divide the difference of the extremes by the number...1, and the quotient will be the common difference required. OBS. The truth of this rule is manifest from Art. 602. 4. The extremes are 5 and 56, and... | |
 | Benjamin Greenleaf - Arithmetic - 1849 - 394 pages
...the number of common differences, the quotient will be the common difference. Thus 16 -;- 8 = 2 is the common difference. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. 1. The extremes are 3 and 45, and the number of terms... | |
 | George Roberts Perkins - Arithmetic - 1849 - 342 pages
...the first term, the last term, and the number of terms, to find the common difference, we have this RULE, Divide the difference of the extremes by the number of terms, less one. EXAMPLES. 1. The first term of an arithmetical progression is 5, the last term is 176, and the... | |
 | Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...quotient will be the common difference. Thus, 27-:-9 = 3, the common difference. Hence the following RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. EXAMPLES FOR PRACTICE. 1. The extremes of a series... | |
 | J. M. Scribner - Mechanical engineering - 1849 - 264 pages
...difference 5 * 20-1 = 19 and 19x^9^; and 91+1 = 10^. Ans. Gicen the Number of Terms and the Extremes, to find the Common Difference. Rule. — Divide the difference of the extremes by one less than the number of terms. Example. — The extremes are 3 and -26, and the number of terms... | |
 | Charles Guilford Burnham - 1850 - 352 pages
...238. — When the extremes and number of terms are given, to find the common difference, we have this RULE. Divide the difference of the extremes by the...1, and the quotient will be the common difference. 7. If the first term of a series be 3, the last term 276, and the number of terms 40, what is the common... | |
 | Roswell Chamberlain Smith - Arithmetic - 1850 - 311 pages
...•*- 5= 5 years, the common difference. A. 5 years. 1 1 . Hence, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will oe the common difference. 12. If the extremes be 3 and 23, and the number of terms 11, what is the... | |
 | Benjamin Greenleaf - Arithmetic - 1850 - 368 pages
...the number of common differences, the quotient will be the common difference. Thus 16 -5- 8 = 2 is the common difference. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. 1. The extremes are 3 and 45, and the number of terms... | |
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PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct. 
