 | Daniel Adams - Arithmetic - 1828 - 264 pages
...difference. Hence, when the extremes and number of tenns are given, to find the common difference, — Divide the difference of the extremes by the number...1, and the quotient will be the common difference. 6. If the extremes be 5 and 605, and the number of terms 151, what is the common difference? Ans. 4.... | |
 | Daniel Adams - Arithmetic - 1828 - 264 pages
...difference. .{fence, when the extremes and number of tenns are given, find the common difference, — Divide the difference of the extremes by the number...1, and the quotient will be the common difference. 6. If the extremes be 5 and 605, and the number of terms 151, what is the common difference ? Ans.... | |
 | Montgomery Robert Bartlett - Education - 1828 - 426 pages
...of this or anyother country. ARITHMETICAL PROGRESSION. LESSON 7. CASE 2d. When the two extremes are given, to find the common difference. , RULE. Divide...difference' of the extremes by the number of terms, less by 1, arid the quotient will be the common difference. Thus:— (1) If the ages of 12 persons are equally... | |
 | Nathan Daboll - Arithmetic - 1828 - 247 pages
...them one by one to the basket ? ,9ns. 23 miles, 5 furlongs, 180 yds. , PROBLEM II. The first termi, the last term, and the number of terms given, to find...the common difference. RULE. Divide the difference ol the extremes by the number of terms less 1, and tne quotient will be the common difrcrence. * ,.... | |
 | William Kinne - 1829 - 248 pages
...the average price was $2,52cts. 5m. per yard. PROBLEM 11. The extremes and the number of terms being given, to find the common difference. • RULE. —...difference of the extremes by the number of terms loss 1, and the quotient will be the common difference. EXAMPLES. 1. The extremes are 3 and 19, and... | |
 | Nathan Daboll - Arithmetic - 1829 - 240 pages
...returning with them one by one to the basket ? Ans. 23 miles, 5 furlongs, 180 yds. PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RUI.K. — Divide the dilFerenre of the extremes liy the number of terms less 1, and the quotient will... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1829 - 250 pages
...middle term, 7, equal 14, and 3+11 = 14* and 5+9=14. Progressions are best understood by Algebra. The first term, the last term, and the number of terms, given to find the sum of all the terms. RULB. Multiply the sum of the two extremes by the number of terms, and half that... | |
 | Nathan Daboll - Arithmetic - 1829 - 268 pages
...to the basket ? Ans. 23 miles, b furlongs, ISQydt PROBLEM II. The first term, the last term, and thr number of terms given, to find the common difference. RULE. Divide the difference of (he extremes by the number of terms less 15 and the quotient •«!! be the common differ.* ence. EXAMPLES.... | |
 | Arithmetic - 1829 - 180 pages
...Hence, when the extremes and number of terms arc gif en, to find the common difference, 371. RILE. Divide the difference of the extremes by the number of terms LESS ONE, and the quotient will be the answer. 7. If the extremes be 7 and 315, and number of terms 78 ;... | |
 | Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...fAcnĄ25-r- 5 =-5 years, the common difference. A.5угs. Hence, to find the common difference ; — Divide the difference of the extremes by the number...1, and the quotient will be the common difference. 2. If the extremes be 3 and 23, and the number of terms l1, what in l ha common difference ? A. 2.... | |
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PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct. 
