| Nathan Daboll - Arithmetic - 1824 - 240 pages
...urst teria, the last term, and the number of terms given, i"fmd the common difference. KULE. Divine **the difference of the extremes by the number of terms...1, and the quotient will be the common difference.** .. EXAMPLES 1. T!ie extremes are 3 and 29, and the numaer o*. terms 1-1, what is the common difference?... | |
| Stephen Pike - Arithmetic - 1824 - 198 pages
...sold at 12 for a farthing? Ans. 86L. 17s. 10d. CASE 2. When the two extremes and number of terms are **given, to find the common difference. RULE. Divide...difference of the extremes by the number of terms, less** one; the quotient will be the common difference. EXAMPLES. 1. Twenty and sixty are the two extremes... | |
| Etienne Bézout - Mathematics - 1824 - 219 pages
...CASE II. When the two extremes and number of terms are giten, to find the common ratio or difference. **Divide the difference of the extremes by the number of terms less 1** ; the quotient witt be the common ratio. EXAMPLES. 1. 20 and 60 are the two extremes of a series in... | |
| Thomas Tucker Smiley - Arithmetic - 1825 - 198 pages
...product will be the sum of all the terms. Case 2. When the first and last terms (or two extremes,) are **given to find the common difference. Rule . Divide...difference of the extremes by the number of terms less 1,** the quotient will be the temmon difference. • Questions. What is Arithmetical Progression ? Name... | |
| Nathan Daboll - Arithmetic - 1825 - 240 pages
...returning with them one by one to the basket ? •Ans. S3 mi1 es, 5 furlongs, IS0 yds. l'IKMïLEM II. The **first term, the last term, and the number of terms given, to** fmd the common diiïereuce. RULE. EXAMPLES. 1. The extremes are 3 and 29, and tlte number ot terms... | |
| Zadock Thompson - Arithmetic - 1826 - 164 pages
...last term, the number of terms, the common difference, and the sum of all the terms. Problem I. The **first term, the last term, and the number of terms given, to find the** sum of all the terms. RULE.* — Multiply the sum of the extremes by the number of terms, and half... | |
| B. M. Tyler - Arithmetic - 1827 - 287 pages
...Ans. 20. 1000, 3, 38, 35891. 21. 120, 6, 11, 990. 22. 1, TV, 40, 244V. 23. 10, 1|, 5, 35. PROBLEM III. **To find the common difference. RULE. Divide the difference of the extremes by** one less than the number of terms. Illustration. — The greater term is made up of the less, and the... | |
| Nathan Daboll - Arithmetic - 1828 - 240 pages
...returning with them one by one to the basket ? Ans. 23 ntiks, 5 furlongs, 180 yds. PROBLEM II. The **first term, the last term, and the number of terms...terms less 1 , and the quotient will be the common** diffcrenct. EXAMPLES. 1. The extremes are 3 and 29, and the number of terms 14, what is the common... | |
| Daniel Parker - Arithmetic - 1828 - 348 pages
...was the average per yard ? Ans. Amount $151 50c<.: average per yard $1 ¡>let. am. PROB. II. — The **first term, the last term, and the number of terms...RULE. Divide the difference of the extremes by the** numbexof terms less one, and the quotient will be the common difference. 1. The extremes are 5 and... | |
| Nathan Daboll - Arithmetic - 1828 - 268 pages
...them one by one to the basket ? . \ffns. 23 miles, 5 furlongs, 1 80 yds. PROBLEM .II. The first termi, **the last term, and the number of terms given, to find...Divide the difference of the extremes by the number** -if tarms less 1? and toe quotient will be the common dif'erence. EXAMPLE8. 1. The extremes are 5 and... | |
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