 | Philotus Dean - Arithmetic - 1874 - 472 pages
...— 1) d, it is plain that I — a = ± \n — Í) d, and d= ± ((I—a) -i- (n — 1)). Hence the Rule. — Divide the difference of the extremes by the number of terms less one. EXAMPLES FOR PRACTICE. 1. The first term is 2, the last term is 74, and the number of terms 25... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...difference of the extremes divided by the number of terms less 1, will be the common difference. Hence the RULE. — Divide the difference of the extremes by the number of terms less 1. EXAMPLES FOR PRACTICE. 1. The extremes of an arithmetical series are 2 and 22, and the number of terms... | |
 | James Bates Thomson - 1875 - 392 pages
...number of terms less i ; therefore iS-ig, or 2, is the common difference required. (Art. 93.) Hence, the RULE. — Divide the difference of the extremes ~by the number of terms less i. 9. The ages of 7 sons form an arithmetical series, the youngest being 2, and the eldest 20 years:... | |
 | James Stewart Eaton - Arithmetic - 1875 - 340 pages
...divided by 3 (15 -i- 3 = 5), gives one of these additions, ie the common th'fference. Hence, EULE. Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. Ex. 1. The extremes of an arithmetical series... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...number of terms less one is 21 ; and 42 ( = 45 — 3) divided by 21 gives 2, the common difference. 524. RULE. — Divide the difference of the extremes by the number of terms less one. vaoni, E 3i s . What is the common difference when 1. The first term is 1, and the 21st, 41 ?... | |
 | Benjamin Greenleaf - Arithmetic - 1876 - 344 pages
...divided by the number of common differences, 9, the quotient, 3, will be the common difference. Hence the RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. EXAMPLES FOR PRACTICE. 1. The extremes of a series... | |
 | James Bates Thomson - 1876 - 400 pages
...I; therefore 18-5-9, or 2, is the common difference required. (Art. 93.) Hence, the RULB.—Divide the difference of the extremes by the number of terms less 1. 9. The ages of 7 sons form an arithmetical series, the youngest being 2, and the eldest 20 years: what... | |
 | Joseph Ray - Arithmetic - 1877 - 402 pages
...divided by 6, the number of 20 — 2 _= I 8 terms less 1, is 3, the common difference. 1 8 -H 6 = 3 Rule. — Divide the difference of the extremes by the number of terms less one. 2. The extremes are 3 and 300 ; the number of terms 10 : find the common difference. 33. 3. A... | |
 | Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1877 - 374 pages
...terms less one ; thus, by taking away 2 in the fifth term, 2 + 3-1-3+3 + 3, we have 3 taken 4 times. RULE. Divide the difference of the extremes by the number of terms less one. 330 ARITHMETICAL PROGRESSION. EXAMPLES FOB PRACTICE. 1. The first term is 2, the last term is... | |
 | Edward Brooks - Arithmetic - 1877 - 528 pages
...substituting the values of the given terms. See Art. 843. Rule. — To find the common difference, divide the difference of the extremes by the number of terms less one. 2. $1600 in 60 years amounts to $8320 ; required the annual interest. Ans. $112. 8. A begins business... | |
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PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct. 
