 | Benjamin Greenleaf - 1854 - 340 pages
...quotient will be the common difference. Thus, 27 -r- 9 = 3, the common difference. Hence the following xj RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. EXAMPLES FOR PRACTICE. 1. The extremes of a series... | |
 | Benjamin Greenleaf - Algebra - 1854 - 298 pages
...first term from the last, we have the difference of the extremes ; thus, \ — J=żAnd, by dividing the difference of the extremes by the number of terms less 1, we have the common difference, | — (5— l)=2Ji =d. e+A=i; i+A=&ˇ -&+A=HThe means, therefore, are... | |
 | Roswell Chamberlain Smith - Arithmetic - 1856 - 344 pages
...then, 25-=-5=5years, the common difference. A. 5 years. 11. Hence, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient Witt te the common difference. 12. If the extremes be 3 and 23, and the number of terms 11, what is'... | |
 | Charles Guilford Burnham - Arithmetic - 1857 - 324 pages
...238* — When the extremes and number of terms are given, to find the common difference, we have this RULE. Divide the difference of the extremes by the...1, and the quotient will be the common difference. 7. If the first term of a series be 3, the last term 276, and the number of terms 40, what is the common... | |
 | James Stewart Eaton - Arithmetic - 1857 - 376 pages
...additions ; ie the coiumon difference. Hence, 346. PROB. 2. — The extremes and number of terms being given, to find the common difference, RULE. — Divide...difference of the extremes by the number of terms less one, and the quotient will be the common difference. Ex. 1. The extremes of an arithmetical series... | |
 | Charles Guilford Burnham - 1857 - 336 pages
...of terms are given, to find the common difference, we have this RULE. Divide the difference of tlie extremes by the number of terms less 1, and the quotient will be the common difference. 7. If the first term of a series be 3, the last term 276, and the number of terms 40, what is the common... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...quotient will be the common difference. Thus, 27 -S- 9 = 3, the common difference. Hence the following RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. EXAMPLES FOR PRACTICE. 1. The extremes of a series... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 444 pages
...3 = 42, divided by the number of common differences, 21, gives 2 as the common difference required. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient will be the common difference. EXAMPLES. 2. A certain school consists of 19 teachers... | |
 | Silas Lawrence Loomis - Arithmetic - 1859 - 324 pages
...PROB. CLIII. — GIVEN, THE EXTREMES AND NUMBER OF TERMS, TO FIND THE COMMON DIFFERENCE AND MEANS. RULE Divide the difference of the extremes by the number of terms, less one, for the common difference. Then construct the series by P/ob. CL. PROB. CLIV. — GIVEN, THE EXTREMES... | |
 | Horatio Nelson Robinson - 1859 - 348 pages
...one ; thus, by taking away 2 in the fifth term, 2-J-3 + 3 + 3 + 3, we have 3 taken 4 times. Hence, RULE. Divide the difference of the extremes by the number of terms less one. EXAMPLES. 1. The first term is 2, the last term is 17, and the number of terms is 6 ; what is... | |
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PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct. 
