Books Books PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct. The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ... - Page 118
by Zadock Thompson - 1838 - 164 pages ## Mathematics: Compiled from the Best Authors and Intended to be the ..., Volume 1

Mathematics - 1801 - 426 pages
...yards. PROBLEM II. lie first term, iJce last term, and the number of terms being given,, to find ike common' difference. RULE.* Divide the difference of the extremes by the number of terms less i, and the quotient will be the common difference sought. EXAMPLES. i. The extremes are 2 and 53, and... ## The Arithmetical Magazine, Or, Mercantile Accountant: Adapted to the ...

William M. Finlay - Accounting - 1803 - 252 pages
...peculiar properties of Progression. PROBLEM IV. Given the first term, the last term, and number of terms, to find the common difference. RULE.— Divide the...difference of the extremes by the number of •terms less I— the quotient will be the common difference. EXAMPLE. jGhren 3, the first, 39 the last, and 19... ## A Treatise of Practical Arithmetic and Bookkeeping, by Single Entry

William Tinwell - Arithmetic - 1805 - 191 pages
...5oo0 yards, or 2 miles and 1^SoyarJt* PROPOSITION 2. When the extremes and the number of terms are given to find the common difference. RULE. — Divide the difference of the extremes, by one lefs than the number of terms, and the quotient will be the anfwer. 1. If the extremes be 2 and... ## Mathematics: Compiled from the Best Authors, and Intended to be ..., Volume 1

Mathematics - 1808 - 470 pages
...term, the .last term, and the number of terms being given, to jind the common difference. RULE 3.* Divide the differe'nce of the extremes by the number...1, and the quotient will be the common difference sought, * The difference of the first and last terms evidently shows the increase of the first term... ## A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - Algebra - 1808 - 468 pages
...hast term. RULE. — Divide the greatest term by such power of the ratio, •whose index is equal to the number of terms less 1, and the quotient will be the least term. EXAMPLE. If the ratio be 2, the number of terms 6, and the greatest term 18 : What is die... ## Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1810 - 180 pages
...difference. Hence, when the extremes and number of terms are given, tn fnd the common difference,—' Divide the difference of the extremes by the number...1, and the quotient will be the common difference. 6. If the extremes be 3 and 603, and the number of terms 131, whnt is the common difference 7 Ans.... ## The American Tutor's Assistant Revised: Or, A Compendious System of ...

Zachariah Jess - Arithmetic - 1810 - 210 pages
...two extremes and number of terms are given, and the common difference of all the terms required ; . Divide the difference of the extremes by the number of terms, less one,, the quotient will be the common difference. E \X AMPLES. l Admit, a debt be discharged at 16... ## The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

Arithmetic - 1811 - 198 pages
...CASE 2. When, the two extremes and number of ternis are given, to find the common difference. RULÉ. . Divide 'the difference of the extremes by the number of terms, less one ; the quotient will be the .common difference. EkAMPLES. , j 1. 20 and 60 are the two extremes... ## Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain and ...

Nathan Daboll - Arithmetic - 1813 - 242 pages
...returning with them rue by one to the basket 1 Ans. 23 miles, 5 furlongs, 180 yds. PROBLEM 11. The first term, the last term, and the number of terms...Divide the difference of the extremes by the number 'f terms leas I... and the quotient will be the common difference. EXAMPLES. 1. The extremes are 3... 