 | Nathan Daboll - Arithmetic - 1815 - 240 pages
...returning with them oae by one to the basket ? - .' . Jlns. 25 miles, 5 furlongs, 180 yds, PROBLEM II. The first term, the last term, and the number of terms...1, and the quotient will be the common difference. EXAMPLE8. 1. The extremes are 3 and 29, and the number oi terms 14, what is the common difference ?... | |
 | Nathan Daboll - Arithmetic - 1817 - 240 pages
...singly, returning with them one by one to the basket? Ans. 23 miles, 5 furlongs, l&dyds. PROBLEM II. The first term, the last term, and the number of terms...common difference. RULE. Divide the difference of tho extremes by the number. ,. of terms less 1, and the quotient will b'e the common difference. EXAMPLES.... | |
 | Arithmetic - 1817 - 198 pages
...2. When the two extremes and number of terms are giren, to iiiid the common ,i;flr.a..«Bee. KPLE. Divide the difference of the extremes by the number of terms, less one ; the quotient will be the common difference. EXAMPLES. 1. 20 and 60 are the two extremes of a... | |
 | Arithmetic - 1818 - 251 pages
...Ans. 5 miles. 233 rods. 2 pr<j5« PROBLEM II. The first term, the last term, and the number of terms to find the COMMON DIFFERENCE. RULE. Divide the difference of the extremes by the number of terms less by i, and the quotient will be the common difference required. EXAMPLES. 1. If the extremes be 3 and... | |
 | Nathan Daboll - Arithmetic - 1820 - 240 pages
...returning with them one by one to the basket ? Jliis. 23 miles, 5 furlongs, 180 yds. PROBLEM II. The first term, the last term, and the number of terms...RULE. Divide the difference of the extremes by the numbor of terms less 1, and the quotient will be the common ihf ference. EXAMPLES, 1. The extremes... | |
 | Nathan Daboll - Arithmetic - 1820 - 240 pages
...returning with them one by one to the basket ? wJ»es. 23 miles, 5 furlongs, 180 yds. PROBLEM II. The first term, the last term, and the number of terms..."" RULE. Divide the difference of the extremes by tta. of terms less 1, and the quotient wiiVte ference. v» v^ EXAMPLES 1. The extremes are 3 and 20,... | |
 | Nathan Daboll - Arithmetic - 1821 - 240 pages
...number of terms given, t« find the common difference. RULE. Divide the difference of the extremes liy the number of terms less 1, and the quotient will be the common dif? ference. I to • A1UTHME A*. aOORESSIOH. i EXAMPLES 1. The extremes are 3 and 29, and the number... | |
 | Nicolas Pike - Arithmetic - 1822 - 532 pages
...first term, the last term, and the number of terms being given, to find the common difference. ROLE.* Divide the difference of the extremes by the number...1, and the quotient will be the common difference sought. EXAMPLES. , 1st. The extremes are 3 and 39, and the number of terms is 19 : What is the common... | |
 | Jacob Willetts - Arithmetic - 1822 - 191 pages
...for a cent ? Ans. $834 16cta. "1 ', CASE 2. When the two extremes and number of terms are given, t« find the common difference. RULE. Divide the difference of the extremes by the number of term^j less one ; the quotient will be the common difference. EXAMPLES. 7. Admit a debt to be discharged... | |
 | Nathan Daboll - Arithmetic - 1823 - 240 pages
...returning with them one by one to the basket ? •tins. 23 miles, 5 furlongs, 180 yds. PROBLEM II. The first term, the last term, and the number of terms given, to fmd the common difference. RULE. • EXAMPJ.ES. 1. The extremes are 3 and 20, anil the number ul terms... | |
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PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct. 
