 | Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...lie. The first term, last term, and number of terms given, to find the sum of all the terms. • ' RULE. Multiply the sum of the extremes by the number...half the product will be the answer. ' EXAMPLES. 1. A man bought 12 yards of cloth in arithmetical progression. For the first yard he gave 6 cents, and... | |
 | Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...multiplied by the number of terms, the product will be double the sum of either series. Hence, 'RuLE I. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE II. — Multiply the sum of the extremes by half the number of terms, and... | |
 | Rufus Putnam - Arithmetic - 1849 - 276 pages
...last term as in 'Case I. , and then multiply the sum of the extremes^ half the number of terms. Or, Multiply the sum of the extremes by the number of terms, and take 4 the product. 8. How many times does the hammer of a clock strike in 12 hours ? (1-1-12) X 12... | |
 | Benjamin Greenleaf - Arithmetic - 1850 - 368 pages
...the extremes be multiplied by the number of terms, the product will be double the sum of the series. RULE. - - Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. 5. The extremes of an arithmetical series are 3 and 45, and the number of terms... | |
 | James Robinson - Arithmetic - 1850 - 342 pages
...series of numbers in arithmetical progression, when we have the extremes and number of terms given. • RULE. Multiply the sum of the extremes by the number of terms, and divide the product by 2, the quotient will be the sum of all the terms. 1. The extremes of* an arithmetical... | |
 | Horatio Nelson Robinson - Algebra - 1850 - 256 pages
...from equation (-B), thus : RULE . — Multiply the sum of the extremes by half the number of terms. EXAMPLES. 1. The first term of an arithmetical series is 5, the last term 92, and the number of terms 30. What is the sum of the terms? Am. 1455. 2. The first term of an... | |
 | Benjamin Greenleaf - 1851 - 332 pages
...multiplied by the number of terms, the product will be double the sum of either series. Hence, RDLE I. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE II. — Multiply the sum of the extremes by half the number of terms, and... | |
 | William Smyth - Algebra - 1851 - 272 pages
...To find, therefore, the sum of all the terms, when the extremes and the number of terms are given, Multiply the sum of the extremes by the number of terms, and take one-half of the product. Ex. 1. In a progression by difference, the first term is 5, the last... | |
 | Benjamin Greenleaf - 1854 - 342 pages
...multiplied by the number of terms, the product will be double the sum of either series. Hence, > RULE I. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE II. — Multiply the sum of the extremes by half the number of terms, and... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...multiplied by the number of terms, the product will be double the sum of either series. Hence, RULE 1. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE 2. — Multiply the sum of the extremes by half the number of terms, and... | |
| |
RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. 
