 | Daniel Adams - Arithmetic - 1848 - 322 pages
...series ; hence, rvhen the extremes and the number of terms are given to find the sum of the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151,... | |
 | James Ryan - Arithmetic - 1827 - 290 pages
...PROBLEM If. — The extremes and the number of terms leing given, to find the sum of the series. 206. RULE. — Multiply the sum of the extremes by the number of terms, and take half the product. * Thereason of this operation will be manifest from the consideration, that... | |
 | Zachariah Jess - Arithmetic - 1827 - 226 pages
...add the first term, the sum is the last term. Secondly, Multiply the sum of the first and last term by the number of terms, and half the product will be the sum of the series. EXAMPLES. 1. Bought 19 yards of shalloon, at 1 cent for the first yard, 3 cents... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...first term, the last term, and the number of terms being given, to find the stun of all the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. Examples. 53+5=68 The sum of the extremes. Then 58x9+2=261 Ans, а. How many strokes... | |
 | Montgomery Robert Bartlett - Education - 1828 - 426 pages
...term, the sum will be the last term. 2. Add the first and the last terms together, and multiply the sum by the number of terms, and half the product will be the sum of all the terms. Thus:— • (1) What is the last term, and the number of terms of an arithmetical... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...Hence, when the. extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Daniel Adams - Arithmetic - 1828 - 266 pages
...Hence, when the extremes and the number of terms are given, '.o find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will b« the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | William Kinne - 1829 - 246 pages
...term, the last term, and the number of terms being given, to find the sum of all the terms. HOLE. — Multiply the sum of the extremes by the number of...answer. EXAMPLES. 1. The first term of an arithmetical progression is 1, the last term 21, the number of terms 11 ; required the *»m of the series. 21 1... | |
 | Nathan Daboll - Arithmetic - 1829 - 252 pages
...process, and are here omitted. F.. — Multiply the sum of the extremes by the nuiL terms, and half tne product will be the answer. EXAMPLES. 1. The first term of an arithmetical series is 3, the last term 28, and the number of term's J 1 ; required the sum of the series. 23+3— 2(J sum... | |
 | Dudley Leavitt - Mathematics - 1830 - 154 pages
...instead of $ 353.50. 16. "If 1000 bricks lie 6 inches from each other in a straight line," &c. Solution. Multiply the sum of the extremes by the number of terms, and half of the product is the answer. 1st. In going from the pile to the first brick, and carrying that brick... | |
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RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. 
