 | William Dodds - 1883 - 198 pages
...divisor, aa it now stands, by this last quotient figure, and subtract the product from the dividend. 6°. To the remainder bring down the next period for a new dividend. Then find a new divisor by doubling the figures of the quotient, and proceed as before, till all the... | |
 | William Allen Sylvester - Carpentry - 1884 - 222 pages
...complete divisor by the trial HOUSE-CARPENTER'S COMPANION. figure in the root, and subtract the product from the dividend ; and to the remainder bring down the next period for a new dividend. 5. To the last complete divisor add the last figure of the root, and to the sum annex one cipher for... | |
 | Benjamin Adams Hathaway - Arithmetic - 1885 - 190 pages
...to the divisor; then multiply the divisor by the last figure in the quotient, subtract the product from the dividend, and to the remainder bring down the next period as before.' Double the whole root as before and place it in the left as a second trial divisor, find... | |
 | Frank Eugene Kidder - Architecture - 1886 - 640 pages
...divisor, multiply this final divisor by the number in the quotient just found, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and proceed as before. If it should be found that the trial divisor cannot be contained in the dividend,... | |
 | M. P. Caldwell - Arithmetic - 1883 - 198 pages
...the true divisor by the last figure placed in the root, and subtract its product from th, dividend. To the remainder bring down the next period for a new dividend and proceed as before. CUBE ROOT. NtTE. — If fractions occur, extract the cube root of the numerator... | |
 | James Morton - Mathematics - 1887 - 236 pages
...hand of the divisor and under the same, and multiply the divisor by this figure. Subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so continue until all the periods are brought down. Jf any dividend shall be too small to contain... | |
 | Horatio Nelson Robinson - 1888 - 372 pages
...complete divisor ; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring 'down the next period for a new dividend. V. To the last complete divisor add the last figure of the root, and to the sum annex one cipher, for... | |
 | Frank Eugene Kidder - Architecture - 1892 - 1032 pages
...divisor, multiply this final divisor by the number in the quotient just found, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and proceed as before. If it should be found that the trial divisor cannot be contained in the dividend,... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. To the last complete divisor add the last figure of the root, and to the sum annex one cipher, for... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
