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Bring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor as before, and in like manner proceed till the whole be finished.
The Youth's Assistant in Theoretic and Practical Arithmetic, : Designed for ... - Page 171
by Zadock Thompson - 1828 - 225 pages

## A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829
...the given number as before. • 7. Bring down the first figure of the next period to the remaimle/Yor a new dividend, to which find a new divisor, and so on, until the whoie ts finished. EXAMPLES. \. What is the cube root of 53157376 ? 53 : 57376(876 root....

## A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - Arithmetic - 1832 - 263 pages
...whole ascertained root to the given power; and subtract it from the first and second periods. Bring down the first figure of the next period to the remainder,...for a new dividend; to which, find a new divisor, as before, and so proceed, till the work is finished. NOTE— The roots of the 4th, 6th, 8th, 9th and...

## The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - Arithmetic - 1832 - 168 pages
...root. Involve the whole root to the given, power; subtract it from the given number as before, bring down the first figure of the next period to the remainder for a new dividend, to which find & new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cube root...

## The Youth's Assistant in Theoretic[!] and Practical Arithmetic ...

Zadock Thompson - Arithmetic - 1832 - 168 pages
...bring down the first figure of the next period to the remainder for a new dividend, to which find & new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cube root of 48228544? 48228544 ( 304 363=46656 362 X3=3708 ) 15725 2d div'd. 3643=48228544 2. What...

## A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - Arithmetic - 1832 - 528 pages
...given power, and subtract it from the gicen number, as before. 7. Bring down the first figure of tho next period to the remainder for a new dividend, to which find a new divisor, as belore and, in like manner, proceed till the whole be finished. EXAMPLES. 1st. What is the cube...

## The North American Arithmetic: for advanced scholars. Part third

Frederick Emerson - Arithmetic - 1834 - 288 pages
...given power, and subtract it from the two left hand periods of the given number. Lastly. — Bring down the first figure of the next period to the remainder, for a new dividend, to which find a new divisor, as before. Thus proceed, till the whole root is extracted. Observe, that when a figure obtained for...

## The New System of Practical Arithmetic: Whereby Most of the Various Problems ...

Charles Potts - Arithmetic - 1835 - 180 pages
...the first and second periods, or from as many periods as you have found periods in the root. Bring down the first figure of the next period to the remainder for a new dividend ; to which find a new divisor as before, and so proceed. NOTE. — The roots of the 4th, 6th, 8th, 9th, and 12th powers may be obtained...

## The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - Arithmetic - 1835 - 198 pages
...whoJe ascertained root to the given power, and subtract it from the first and second periods. Bring down the first figure of the next period to the remainder, for a ne\v dividend; to which, find a new divisor, as before; anc! so prrcced. Note. — The roots of the...