| Nathan Daboll - Arithmetic - 1818 - 240 pages
...(always) from as many periods of the given num * ber as you have found figures in the root. 7. Bringdown **the first figure of the next period to the remainder for a new dividend, to which find a new divisor,** as before, and in like manner proceed till the whole be finished. NOTE. — When the number to be subtracted... | |
| Nathan Daboll - Arithmetic - 1820 - 240 pages
...(always) from as many periods of the given number us you have fuund figures in the root. 7. Bringdown **the first figure of the next period to the remainder for a new dividend, to which find a new divisor,** as before, and in like manner proceed till the whole be finished. NOTE. — When the number to be subtracted... | |
| Nathan Daboll - Arithmetic - 1820 - 240 pages
...the given number as you have found figures in the root. 7. Bring down the first figure of the nest **period to the remainder for a new dividend, to which find a new divisor,** as before, and in like manner proceed till the whole be finished. NOTE. — When the number to be subtracted... | |
| Jacob Willetts - Arithmetic - 1822 - 191 pages
...whole ascertained root to the given power, and , subtract it from the first and second periods. Bring **down the first figure of the next period to the remainder...for a new dividend ; to which, find a new divisor,** as before, and so proceed. Note — The roots of the 4th, 6th, 8th, 9th and 12th powers, may be obtained... | |
| Stephen Pike - Arithmetic - 1824 - 198 pages
...whole ascertained root to the given Dower, and subtract it from the first and second peiods. Bring **down the first figure of the next period to the remainder,...for a new dividend; to which, find a new divisor,** as before; and so proceed. Note.— The roots of the 4th, 6th, 8th, 9th, and 1.2th Dowers, may be obtained... | |
| Zadock Thompson - Arithmetic - 1826 - 164 pages
...root. 5. Involve the whole root to the given power ; subtract it from the given number as before, bring **down the first figure of the next period to the remainder...new divisor, and so on till the whole is finished.** Examples. 1. What is the cube root of 48228544 ? 48228544(364 33=27 32X3=27)212 dividend. 363 =46656... | |
| Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 200 pages
...to a sixth power ; and extracting the square root of the sixth power reduces itto a cube. 7. Bring **down the first figure of the next period to the remainder for a new dividend, to which find a new divisor,** as before, and in like manner proceed till the whole be finished. EXAMPLES. 1. What is the cube root... | |
| Nicolas Pike, Dudley Leavitt - Arithmetic - 1827 - 200 pages
...to a sixth power; and extracting the square root of the sixth power reduces it to a cube. 7. Bring **down the first figure of the next period to the remainder for a new dividend, to which find a new divisor,** as before, and in like manner proceed till the whole be finished. EXAMPLES. 1. What is the cube root... | |
| Nathan Daboll - Arithmetic - 1828 - 240 pages
...(always) from as many periods ol the given num ber as you have found figures in the root. r. Bringdown **the first figure of the next period to the remainder for a new dividend, to which find a new** divi•or, as before, and in Kke manner proceed till the whole be finished. . NOTE. — When the number... | |
| Daniel Parker - Arithmetic - 1828 - 348 pages
...Involve the whole root to the given power, and subtract it uom the given number, as before. 7. Bring **down the first figure of the next period to the remainder for a new** resolver«! ; find a new divisor as before, ano proceed in like manner until the whole is finished.... | |
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