| William Kinne - Accounting - 1831 - 240 pages
...for the first figure of the root; and set the square number under the period, subtract it therefrom, **and to the remainder bring down the next period for a dividend.** 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4. Consider... | |
| Zadock Thompson - Arithmetic - 1832 - 168 pages
...find the greatest cuhe in the left hand period, and place its root in the quotient. Subtract the cube **from the left hand period, and to the remainder bring down the next period for a dividend.** Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, calling... | |
| William Ruger - Arithmetic - 1832 - 263 pages
...so on. 2. Find the first figure of the root by the table of powers, or by trial; subtract its power **from the left hand period, and to the remainder bring down the** first figure in the next period for an imperfect dividend. 3. Involve the root to the next inferiour... | |
| Daniel Adams - Arithmetic - 1833 - 264 pages
...the left band period, and write its root as a quotient in division. Subtract the square number.from **the left hand period, and to the remainder bring down the next period for a dividend.** . III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
| William Templeton (engineer.) - 1833
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, **and to the remainder bring down the next period for a dividend.** Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... | |
| Catharine Esther Beecher - Arithmetic - 1833 - 283 pages
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, **and to the remainder bring down the next period, for a dividend.** 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor.... | |
| Frederick Emerson - Arithmetic - 1834 - 288 pages
...square in the left hand period, and write its root in the quotient. Subtract the square of this root **from the left hand period, and to the remainder bring- down the next period for a dividend.** Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... | |
| Charles Potts - Arithmetic - 1835 - 180 pages
...cube in the left hand period, and set its root on the right of the given number ; subtract said cube **from the left hand period, and to the remainder bring down the next period for a** dividual. 3. Square the root, and multiply the square by 3 for a defective divisor. 4. Reserve, mentally,... | |
| Benjamin Snowden - 1835
...and put its root for the first figure of the root sought. 2. — Subtract this cube from the first **period, and to the remainder bring down the next period for a dividend.** 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this... | |
| Arithmetic - 1835 - 198 pages
...root. 2. lind the first figure of the root by the table of powers, or by trial ; subtract its power **from the left hand period, and to the remainder bring down the** first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that... | |
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