Books Books Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend... The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ... - Page 105
by Zadock Thompson - 1848 - 168 pages ## A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - Accounting - 1831 - 240 pages
...for the first figure of the root; and set the square number under the period, subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4. Consider... ## The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - Arithmetic - 1832 - 168 pages
...find the greatest cuhe in the left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, calling... ## A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - Arithmetic - 1832 - 263 pages
...so on. 2. Find the first figure of the root by the table of powers, or by trial; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for an imperfect dividend. 3. Involve the root to the next inferiour... ## Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1833 - 264 pages
...the left band period, and write its root as a quotient in division. Subtract the square number.from the left hand period, and to the remainder bring down the next period for a dividend. . III. Double the root already found for a divisor ; seek how many times the divisor is contained in... ## The millwright & engineer's pocket companion

...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... ## Arithmetic Simplified in Three Parts

Catharine Esther Beecher - Arithmetic - 1833 - 283 pages
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, and to the remainder bring down the next period, for a dividend. 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor.... ## The North American Arithmetic: for advanced scholars. Part third

Frederick Emerson - Arithmetic - 1834 - 288 pages
...square in the left hand period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... ## The New System of Practical Arithmetic: Whereby Most of the Various Problems ...

Charles Potts - Arithmetic - 1835 - 180 pages
...cube in the left hand period, and set its root on the right of the given number ; subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root, and multiply the square by 3 for a defective divisor. 4. Reserve, mentally,... ## A brief compendium of arithmetic

Benjamin Snowden - 1835
...and put its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this... 