| George Augustus Walton - Arithmetic - 1864 - 348 pages
...the left hand period, and write its root as the first term in the answer. Subtract the square number **from the left hand period, and to the remainder bring down the next period for a dividend.** Take twice the root already found for a trial divisor ; rejecting the right hand figure of the dividend,... | |
| George Augustus Walton - Arithmetic - 1864 - 348 pages
...cube in the left hand period, and write its root as the first term in the answer. Subtract the cube **from the left hand period, and to the remainder bring down the next period for a dividend.** Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
| Thomas Kimber - Mathematics - 1865 - 192 pages
...the left hand, and subtract it from that period> putting down its root on the right, as in division. **To the remainder bring down the next period for a dividend: double the root** just found for a divisor, and find how often it is contained in this dividend exclusive of the figure... | |
| Joseph Ray - Algebra - 1866 - 406 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left **period, and to the remainder bring down the next period for a dividend.** 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
| Joseph Ray - Algebra - 1866 - 240 pages
...the right, after the manner of a quotient in division. Subtract the square of the root from the left **period, and to the remainder bring down the next period for a dividend.** 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
| Joseph Ray - Algebra - 1852 - 396 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left **period, and to the remainder bring down the next period for a dividend.** 3rd. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
| Horatio Nelson Robinson - Algebra - 1866 - 312 pages
...root for the first figure in the required root ; subtract the square of this figure from the first **period, and to the remainder bring down the -next period for a dividend.** III. Double the root already found, and write the result on the left for a divisor ; find how many... | |
| Robert Thomson (of Southampton.) - Marine engineers - 1866 - 143 pages
...number : cube this figure placed in the quotient and place its product under the first period, subtract **and to the remainder bring down the next period for a dividend.** Example 1st. — Extract the cube or third root of 312908547060. 6x6=36 6x3=18x6= 10800 187x7= 1309... | |
| Thomas Percy Hudson - Arithmetic - 1866
...and put down its square root for the first figure of the required whole square root. To the right of **the remainder bring down the next period for a dividend. Double the** part of the square root already found, and place it on the left of this dividend for a partial divisor... | |
| Ezra S. Winslow - Business mathematics - 1867 - 220 pages
...quotient figure to a power corresponding with the denomination of the root sought, and subtract that power **from the left hand period, and to the remainder bring down the** first figure of the next period, for a dividend. 3. Raise the root thus far found (the quotient figure)... | |
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