 | B. M. Tyler - Arithmetic - 1827 - 308 pages
...81900. • * " * PROBLEM II. To find the greatest common divisor, or measure of two numbers. RULE. Divide the greater number by the less, and the divisor by the remainder. Continue to divide the last divisor by the last remainder until nothing remains : the last divisor... | |
 | James Ryan - Arithmetic - 1827 - 290 pages
...to the other, problems VII. &c. If there be a remainder, divide the less by it ; and thug proceed, always dividing the last divisor by the last remainder, till nothing remains. The divisor which leaves no remainder, is the common measure required. If the divisor which leaves... | |
 | Daniel Adams - Arithmetic - 1828 - 266 pages
...finding the greatest common divisor of two numbers : — Divide, the greater number by tbe less, and that divisor by the remainder, and so on, always dividing...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...fmding the greatest common divisor of two numbers : — Divide the greater number by the less, and that divisor by the "remainder, and so on, always dividing...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Nathan Daboll - Arithmetic - 1828 - 268 pages
...a common measure, by dividing the greater term by the less, and this divisor by the remainder, ami so on, always dividing the last divisor by the last remainder, till nothing remams, the last divisor is the common measure.* 2. Divide both of the terms of the fraction by the... | |
 | Nathan Daboll - Arithmetic - 1829 - 252 pages
...common measure, by dividing the greater term by the Ions, and this divisor by the remainder, and pn on, always dividing the last divisor by the last remainder, till nothing remaini', the last divisor is the common measure.* 2. Divide both of the terms of the fraction by the... | |
 | Daniel Adams - Arithmetic - 1830 - 268 pages
...finding the greatest common divisor of two numbers : — Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Daniel Adams - Arithmetic - 1830 - 294 pages
...finding the greatest common divisor of two numbers : — Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Nathan Daboll - Arithmetic - 1830 - 256 pages
...RULE. 1. Find a common measure, by dividing the greater term by the less, and this divisor by live remainder, and so on, always dividing the last divisor by the last remainder, till nothing remains ; the last divisor is the common measure * 2. Divide both of the terms of the fraction by the common... | |
 | Frederick Augustus Porter Barnard - Arithmetic - 1830 - 308 pages
...the greatest common measure of two numbers, DIVIDE THE GREATER NUMBER ВТ THE LESS, THAT DIVISOR BV THE REMAINDER, AND SO ON, ALWAYS DIVIDING! THE LAST DIVISOR BY THE LAST REMAINDER, UNTIL SOME REMAINDER IS LEFT. TlIE DIVISOR WHICH LEAVES NO BEUAINDKB IS THE GREATEST COMMON MEASURE.... | |
| |
Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain. 
