 | George Alfred - Arithmetic - 1834 - 336 pages
...right by Practice Ans. 248 09", and.Duodecimals. PROBLEM 2. To find the area or superficial content of a parallelogram or long square. RULE. , Multiply the length by the breadth, and the product will be tht area or superficial content required. EXAMPLES. 1. What is the superficial content of a plank that... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...which is the answer. TIMBER MEASURE. PROBLEM I. To find the tuperficial content of a board or planfc. RULE. Multiply the length by the breadth, and the product will be the area. Nate. When the plank is broader at one end than at the other, add both ends together, and take half... | |
 | Tobias Ostrander - Measurement - 1834 - 182 pages
...difference and the sum will be the length of the longest side, subtracted leaves the shortest, then multiply the length by the breadth and the product will be the area. EXAMPLES. i 1. The sum of the two adjacent sides of a rectangular parallelogram is 50 chains, and the... | |
 | Education - 1835 - 496 pages
...V imrallelogram is a four-sided right-angled figure, longer than broad. TO MEASURE A PARALLELOGRAM. Multiply the length by the breadth, and the product will be the area. .V. How many feet does a floor in the form of a parallelogram measure, wluimi length is 24 feet, 6... | |
 | William Ruger - Arithmetic - 1836 - 274 pages
...and 20ft. long? Ans, 80yds. NOTE. — To obtain the surface of a plane, as a floor, field., if-e.- Multiply the length by the breadth, and the product will be the surface; then as the number of square feet in a yard of the carpeting which is 4,5 feet, is to one... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...which is the answer. TIMBER MEASURE. PROBLEM I. To find the superficial content of a board or plank. RULE. Multiply the length by the breadth, and the product will be the area. BY THE CARPENTER'S RULE. Set 12 on B, to the breadth in inches on A ; then against the length in feet,... | |
 | Luther Ainsworth - Arithmetic - 1837 - 306 pages
...denomination required. Q. How do you find the superficial area of a parallelogram, or long square ? A. Multiply the length by the breadth, and the product will be the superficial area as before. 1. There is a garden, laid out in an exact square, measuring, on each side,... | |
 | Thomas Holliday - Surveying - 1838 - 404 pages
...it stand upon ? PROBLEM IV. Answer, 4134.49 feet. TO FIND THE AREA OF A RECTANGLE. Rule.—Multiply the length by the breadth, and the product will be the area. Note. Buildings, streets, drains, new roads, &c., are in general rectangles; and artificers generally... | |
 | Nathan Daboll - 1839 - 220 pages
...whole number of square rods to acres.] Ans. 26 acres 1 r. 25 rods. PROB. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the...by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden which is 126 feet long and 65... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...given, to find the area ; or the area and one side given, to find the length of the other aide. RULE. 1. Multiply the length by the breadth, and the product will be the area. 2. Divide the area by one of the sides, and the quotient will be the adjacent side. Examples. 1. What... | |
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To measure a parallelogram or long square. RULE.— Multiply the length by the breadth, and the product will be the area, or superficial content, in the same name as that in which the dimension was taken, whether inches, feet, or rods, etc. 
