 | Daniel Adams - Measurement - 1850 - 144 pages
...&c. ^T ST. The length and breadth of a square or rectangle being give?i, to find the square contents, Multiply the length by the breadth, and the product will be the square contents. NOTE. For an analysis of the principles of this and the following rule, see Revised... | |
 | Sir Henry Edward Landor Thuillier - Surveying - 1851 - 826 pages
...• - - «7 ^ 1568160 = 10890 6272640 = 43560 To determine the area of a Rectangular Parallelogram. RULE. — Multiply the length by the breadth and the product •will be the area. EXAMPLES. Suppose the side of a square to be 10 Chs. 48 Lks. what is the area ? Answer, 10 Acr. 3 Rd.... | |
 | Chambers W. and R., ltd - 1859 - 344 pages
...&c. — thus, for 6 inches, take the .1 of 1 foot ; and so on. I. To FIND THE AREA OF A BECTANGLE. RULE. — Multiply the length by the breadth, and the product will be the area. Example 1. — What is the area of a rectangle, whose length is 4 feet and breadth 3 feet? 4 X 3 =... | |
 | William Keane (gardener.) - 1861 - 252 pages
...a rectangular piece of ground whose length is 16 chains 64 links, and breadth is 7 chains 44 links. Rule : — Multiply the length by the breadth, and the product will be the content. 16-64 7-44 6656 6656 •3 11648 8 10) 123.8016 1C cLaius 64 finks. 12,38016 4 1-52064 40 AR... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...row. We multiply the number of squares in one row by the number of rows; C x 3 = 1C square rods, Ans. RULE. — Multiply the length by the breadth, and the product will be the square contents. NOTE 4. — A line 3 times 5 rods long, is a line 15 rods long. Hence the pupil must... | |
 | Charles Davies - Arithmetic - 1861 - 496 pages
...therefore, the whole number of squares will be equal to 9 x 6 =-54. Hence, to find the area, or measure, Multiply the length by the breadth, and the product will be the number of squaren. NOTE. — The square which is the unit of surface, is the square described on the... | |
 | Stoddard A. Felter - Arithmetic - 1864 - 412 pages
...yard there are 9 square feet. Hence to find the area of any parallelogram, is deduced the following RULE. — Multiply the LENGTH by the BREADTH, and the product will be the square contents. (c.) There is a difference in meaning between such expressions as Jive feet square... | |
 | Charles Davies - Arithmetic - 1865 - 468 pages
...therefore, the whole number of squares will be equal to 9 x 6 = 54. Hence, to find the area, or measure, Multiply the length by the breadth, and the product will be the number of squares. NOTE. — The square which is the unit of surface, is the square described on the... | |
 | Hoy D. Orton - Mathematics - 1866 - 202 pages
...-Arrange the example as below ; (divide both terms by 4X4:) 36X36 9X9 same as =8.1 acres, or8ac. 16 rods. To measure a parallelogram or long square. RULE. —...product will be the area, or superficial content, in the same name as that in which the dimension was taken, whether inches, feet, or rods, etc. EXAMPLES... | |
 | Stoddard A. Felter - Arithmetic - 1866 - 338 pages
...there are 9 square feet. Hence to find the area of any parallelogram, we have the following • (a.) Rule. — Multiply the LENGTH by the BREADTH, and the product will be the surface. ILLUSTRATION. 1 yard=3 feet. 1st row of feet. 2d row of feet. 3d row of feet. i 1st sq. ft.... | |
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To measure a parallelogram or long square. RULE.— Multiply the length by the breadth, and the product will be the area, or superficial content, in the same name as that in which the dimension was taken, whether inches, feet, or rods, etc. 
