A System of Practical Arithmetic: Applicable to the Present State of Trade, and Money Transactions: Illustrated by Numerous Examples Under Each Rule; for the Use of Schools |
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Page 36
... pounds troy are there in 5987 pennyweights ? 5. In 1434 lb. 0 oz . o dwts . 19 grs . how many grains ? 6. How many pounds are there in 45065 grains ? 7. Reduce 105 lbs . troy into grains . 8. In 495 spoons , weighing 103 lbs . 1 oz . 10 ...
... pounds troy are there in 5987 pennyweights ? 5. In 1434 lb. 0 oz . o dwts . 19 grs . how many grains ? 6. How many pounds are there in 45065 grains ? 7. Reduce 105 lbs . troy into grains . 8. In 495 spoons , weighing 103 lbs . 1 oz . 10 ...
Page 37
... pounds 14 pounds 28 pounds 4 quarters , or 112 lb. 20 hundred weight make 1 ounce , Oz . 1 pound , NOTES . b . 1 stone of meat . + 1 stone , horseman's weight . 1 quarter , qr . 1 hundred weight , cwt . 1 ton . he be not quite expert in ...
... pounds 14 pounds 28 pounds 4 quarters , or 112 lb. 20 hundred weight make 1 ounce , Oz . 1 pound , NOTES . b . 1 stone of meat . + 1 stone , horseman's weight . 1 quarter , qr . 1 hundred weight , cwt . 1 ton . he be not quite expert in ...
Page 38
... pound : and again by 16 and take in the 8 , because 16 drams make an ounce . 506013 8096204 16 48577232 8096204 Answer , 129539272 drams . 129539272 NOTE . HAY WEIGHT . 56 lbs . of old hay 60 lbs . of new hay } 1 truss . 36 trusses 1 ...
... pound : and again by 16 and take in the 8 , because 16 drams make an ounce . 506013 8096204 16 48577232 8096204 Answer , 129539272 drams . 129539272 NOTE . HAY WEIGHT . 56 lbs . of old hay 60 lbs . of new hay } 1 truss . 36 trusses 1 ...
Page 39
... pounds , I have two remainders , viz . 1 and 2 , to find the value of which , I multiply the last re- mainder 2 , by the first divisor 4 , and take in the 1 , which make 9 ounces . For the same reason the remainder 3 is equal to 21 lb ...
... pounds , I have two remainders , viz . 1 and 2 , to find the value of which , I multiply the last re- mainder 2 , by the first divisor 4 , and take in the 1 , which make 9 ounces . For the same reason the remainder 3 is equal to 21 lb ...
Page 40
... pounds by 12 , and take in the 5 , because 12 ounces make a pound : afterwards by 8 , 3 , and 20 , taking in the several drams , scruples , and grains , as in the former articles .. Answer - 14197 grains . Ex . 2. In 42591 grains , how ...
... pounds by 12 , and take in the 5 , because 12 ounces make a pound : afterwards by 8 , 3 , and 20 , taking in the several drams , scruples , and grains , as in the former articles .. Answer - 14197 grains . Ex . 2. In 42591 grains , how ...
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A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce No preview available - 2018 |
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce No preview available - 2015 |
Common terms and phrases
9 Ex acres aliquot amount annual annuity annum answer arithmetical progression Avoirdupois bill bushels common denominator compound interest containing cost course of exchange cube root cubic cyphers decimal difference ditto divide dividend divisor equal EXAMPLES farthings feet figures find the value fraction gallons geometrical progression geometrical series given number given sum gives guineas per cent hogsheads hundred improper fractions inches insure joint lives last term lease logarithm London measure miles millions mixed numbers months multiplicand Multiply the number neat weight NOTE number of terms ounces paid payment pence person aged piastre pound sterling pounds present value purchase quantity quotient Reduce remainder Rule of Three shews shillings square root sterling subtract supposing tare thousand tons tret Troy TROY WEIGHT whole number wine worth yards
Popular passages
Page 177 - Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time, nearly.
Page 112 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 243 - Multiply each term into the multiplicand, beginning at the lowest, by the highest denomination in the multiplier, and write the result of each under its respective term ; observing to carry an unit for every 12, from each lower denomination to its next superior.
Page 92 - III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term.
Page 150 - The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.
Page 113 - Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Page 243 - In like manner, multiply all the multiplicand by the inches and parts of the multiplier, and set the result of each term one place removed to the right hand of those in the multiplicand...
Page 55 - Place the numbers so that those of the same denomination may stand directly under each other.
Page 149 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Page 28 - ... the number in the quotient. Multiply the divisor by the quotient figure, and set the product under that part of the dividend used. Subtract the product, last found, from that part of the dividend under which...