Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain Practical System of Arithmetic, Adapted to the United States |
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Page 182
... inches in diameter , in a cer- tain time ; I demand what the diameter of another pipe must be , to discharge four ... inch . diam . Aus . PROB . VI . The sum of any two numbers 182 EVOLUTION , OR EXTRACTION OF ROOTS :
... inches in diameter , in a cer- tain time ; I demand what the diameter of another pipe must be , to discharge four ... inch . diam . Aus . PROB . VI . The sum of any two numbers 182 EVOLUTION , OR EXTRACTION OF ROOTS :
Page 186
... inches . I demand the side of a cubic box , which shall contain that quantity ? 2150,425 12,907 inch . Ans . Note ... inches diameter , weigh 4lb . what will a bullet of the same metal weigh , whose diameter is 6 inches ? 3x3x3 = 27 6 ...
... inches . I demand the side of a cubic box , which shall contain that quantity ? 2150,425 12,907 inch . Ans . Note ... inches diameter , weigh 4lb . what will a bullet of the same metal weigh , whose diameter is 6 inches ? 3x3x3 = 27 6 ...
Page 200
... inch the second , and three inches the third second of time , and so continue to increase its motion in triple pro portion geometrical ; how many yards would the said body move in the term of half a minute ? Ars . 953199685623 yds . Ift ...
... inch the second , and three inches the third second of time , and so continue to increase its motion in triple pro portion geometrical ; how many yards would the said body move in the term of half a minute ? Ars . 953199685623 yds . Ift ...
Page 220
... inches in a superficial foot , & c . ART . I. To find the area of a square having equal sides . RULE . Multiply the ... inches road ; how many square feet are contained in it ? 118 inches 1,5 feet , then 21 × 1,5 - S1,5 Ans . Or , in ...
... inches in a superficial foot , & c . ART . I. To find the area of a square having equal sides . RULE . Multiply the ... inches road ; how many square feet are contained in it ? 118 inches 1,5 feet , then 21 × 1,5 - S1,5 Ans . Or , in ...
Page 221
... inches , and the perpendicular height 14 inches . 52 × 7 = 224 square inches , the Answer . 2. There is a triangular or three cornered lot of land whose base or longest side is 514 rods ; the perpendicular from the corner opposite the ...
... inches , and the perpendicular height 14 inches . 52 × 7 = 224 square inches , the Answer . 2. There is a triangular or three cornered lot of land whose base or longest side is 514 rods ; the perpendicular from the corner opposite the ...
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Common terms and phrases
100 dollars 2qrs annex annuity annum answer Anthony Billings barter Bought bushels cloth compound interest contain cube root cyphers Deduct demand dimes divide the product dividend divisor dols equal EXAMPLES federal money figure Find the value gain or loss gallon given number given sum gross guineas hhds hogshead hundred improper fraction inches least common least common multiple left hand lowest terms measure miles mills milreas mixed numbers months Multiply the given neat weight New-England currency New-Jersey New-York currency NOTE Nova-Scotia currency number of shillings paid payment pence piece pound pound sterling present worth principal quotient rate per cent ratio ready money Reduce remainder Required the interest right hand rods Rule of Three sell separatrix simple interest sold solid feet Sqrs square root sterling subtract subtrahend sugar tare third Thomas Grosvenor trett VULGAR FRACTIONS whole numbers wine