The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
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Page 28
... evidently the product of 0.5 by Ans . 0.25 ft . 10.5 0.5 1 foot . 0.5 ft . Here we perceive that multiplication by a decimal diminishes the multiplicand , or , in other words , gives a product which is less than the multiplicand . 4. If ...
... evidently the product of 0.5 by Ans . 0.25 ft . 10.5 0.5 1 foot . 0.5 ft . Here we perceive that multiplication by a decimal diminishes the multiplicand , or , in other words , gives a product which is less than the multiplicand . 4. If ...
Page 43
... evidently as many pence in 4247gr . as there are times 4 in that number . is 1061 d . and 3qr . over . Then , as it takes 12 pence We therefore divide by 4 , and the quotient to make 1s . there will be as many shillings as there are ...
... evidently as many pence in 4247gr . as there are times 4 in that number . is 1061 d . and 3qr . over . Then , as it takes 12 pence We therefore divide by 4 , and the quotient to make 1s . there will be as many shillings as there are ...
Page 48
... evidently add pence to pence , shillings to shillings , & c . we write down the numbers so that pence shall stand under pence , shillings under shillings , and so We then add the pence , and find their sum to be 15d . but as 12d . Is ...
... evidently add pence to pence , shillings to shillings , & c . we write down the numbers so that pence shall stand under pence , shillings under shillings , and so We then add the pence , and find their sum to be 15d . but as 12d . Is ...
Page 52
... evidently 6 times gr . the cost of 1lb . ; we 6 therefore multiply 8 . 1 6 Aus . 9 4 2 the price of 1lb . by 6 ; thus , 6 times 3qrs . are 18qr . 4d . 2qr . , 154. 1. If 6lb . of coffee cost 9s . 4d . 2qr . , how much is that per lb ...
... evidently 6 times gr . the cost of 1lb . ; we 6 therefore multiply 8 . 1 6 Aus . 9 4 2 the price of 1lb . by 6 ; thus , 6 times 3qrs . are 18qr . 4d . 2qr . , 154. 1. If 6lb . of coffee cost 9s . 4d . 2qr . , how much is that per lb ...
Page 54
... evidently 91 3pk . 3 13pk . went 13 ) 364 ( 28 times 26 104 101 as many times as there are times 13 ( in 91bu . after being re- duced to pecks , i . e . ) in 364pks . , which we find by dividing , to be 28 times . Hence When it is ...
... evidently 91 3pk . 3 13pk . went 13 ) 364 ( 28 times 26 104 101 as many times as there are times 13 ( in 91bu . after being re- duced to pecks , i . e . ) in 364pks . , which we find by dividing , to be 28 times . Hence When it is ...
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Common terms and phrases
3qrs acres Addition amount ANALYSIS answer Arithmetic bush bushels called ciphers circumference column common denominator common difference compound interest contains cost cube root cubic decimal denoted diameter divi divide dividend division dollars dolls DRY MEASURE equal evidently expressed factors Federal Money feet long foot gain gallon given number given to find greatest common divisor Hence hundred hundredths inches least common multiple least terms left hand leger lemons length man's share merator method miles minuend mixed number months multiplicand multiply number of figures number of terms payment pence pound present worth principal proportion quantity quarts QUESTIONS FOR PRACTICE ratio Reduce remainder right hand rods RULE RULE.-Divide RULE.-Multiply shillings side simple solid square root subtract subtrahend supposed tens tenths tion Troy weight units velocity vulgar fraction weight whole number write
Popular passages
Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...
Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...
Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.