The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
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Page 11
... dollars , what was the sum divided ?. Ans . 5984 dolls . 14. If a man's income be 1 dollar a day , what will be the amount of his income in 45 years , allowing 365 days to each year ? Ans . 16425 dolls . 15. A certain brigade con- sists ...
... dollars , what was the sum divided ?. Ans . 5984 dolls . 14. If a man's income be 1 dollar a day , what will be the amount of his income in 45 years , allowing 365 days to each year ? Ans . 16425 dolls . 15. A certain brigade con- sists ...
Page 12
... dollars apiece ; what did they all cost ? If we multiply 17 by 5 , we find the cost at 5 dollars apiece , Operation , and since 15 is 3 times 5 , the cost , at 15 dollars apicce , will manifestly be 3 times as much as the cost at 5 dollars ...
... dollars apiece ; what did they all cost ? If we multiply 17 by 5 , we find the cost at 5 dollars apiece , Operation , and since 15 is 3 times 5 , the cost , at 15 dollars apicce , will manifestly be 3 times as much as the cost at 5 dollars ...
Page 13
... dollars , of which he paid 43 dollars ; how much remains to be paid ? Operation . From 75 minuend . Take 43 subtrahend . - 82 remainder . Now to find the difference between 75 and 43 , we write down the 75 , calling it the minuend , or ...
... dollars , of which he paid 43 dollars ; how much remains to be paid ? Operation . From 75 minuend . Take 43 subtrahend . - 82 remainder . Now to find the difference between 75 and 43 , we write down the 75 , calling it the minuend , or ...
Page 14
... dollars , of which he paid 542 dollars ; how much remains unpaid ? 727 dolls . 542 dolls . Here we take 2 from 7 , and write the difference , 5 , below the line in the place of units . We now proceed to the tens , but find we cannot ...
... dollars , of which he paid 542 dollars ; how much remains unpaid ? 727 dolls . 542 dolls . Here we take 2 from 7 , and write the difference , 5 , below the line in the place of units . We now proceed to the tens , but find we cannot ...
Page 15
... dollars , and he pay you at one time , 86 dollars , and at another 125 dollars , how much is still due ? Ans . 554 dolls . 13. Supposing a man to have been born in 1796 , how old was he in 1828 ? Ans . 32 years . 14. If a man have 125 ...
... dollars , and he pay you at one time , 86 dollars , and at another 125 dollars , how much is still due ? Ans . 554 dolls . 13. Supposing a man to have been born in 1796 , how old was he in 1828 ? Ans . 32 years . 14. If a man have 125 ...
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Common terms and phrases
3qrs acres Addition amount ANALYSIS answer Arithmetic bush bushels called ciphers circumference column common denominator common difference compound interest contains cost cube root cubic decimal denoted diameter divi divide dividend division dollars dolls DRY MEASURE equal evidently expressed factors Federal Money feet long foot gain gallon given number given to find greatest common divisor Hence hundred hundredths inches least common multiple least terms left hand leger lemons length man's share merator method miles minuend mixed number months multiplicand multiply number of figures number of terms payment pence pound present worth principal proportion quantity quarts QUESTIONS FOR PRACTICE ratio Reduce remainder right hand rods RULE RULE.-Divide RULE.-Multiply shillings side simple solid square root subtract subtrahend supposed tens tenths tion Troy weight units velocity vulgar fraction weight whole number write
Popular passages
Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...
Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...
Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.