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If a man purchase a yoke of A certain field has four sides, oxen for £15 59. 8d., four cows whose lengths are as follows: for £20 10s. 6d., and horse 4ch. 27lin. 5ch. 19lin. 4ch. for £26; what did they all 50lin. and 6ch. 4lin. ; what is cost? Ans. £61, 16s. 2d. the distance round it ?
Ans. 20 ch. The floors of 4 rooms in a certain house cover 5rd. 24in. What is the weight of 3hhd. of land; the remaining room of sugar, the first weighing lrd. lyd. Ift.; and the walls 10cwt. 20lb. ; the 2d, Icwt and chimney cover 2rd. llin.; lqr. 1502.; and the 3d, 11cwt. how much land does the whole 15lb. 14dr.? house occupy?
Ans. 1 ton, 10 cwt. 2 qr. 7 Ile Ans. Prd. lyd. Ift. 35in.
15 om 14 de
3. Subtraction. 149. 1. A person bought a cow for £3 7s. 6s., and sold it for £4 12s. Sd., how much did he gain
We write the less number under the greater, so that £
pence shall stand under pence, shillings under sbil4 12 3 lings, and pounds under pounds; we then begin at
the right hand, but as we cannot take 6d. from 3d.,
we borrow from the 12s. Is.=12d., which we join with Gain 1 9 the 3d., making 15d., and then 6d. from 15d. leaves
9d., which we write under the pence. We now proProof 4 12 3 ceed to the shillings, but as we have borrowed ls. from
12s. we call the 12s. 11s., and 7s. from 11s. leaves 48., and lastly, £3 from £4 leaves £1. Thus we find that he gained £1 4s. Id. The above process is called Compound Subtraction.
COMPOUND SUBTRACTION 150. Is the taking of one compound number from another, so as to find the difference between them. (42)
RULE. 151. Write the less number under the greater, so that the parts which are of the same name may stand directly under each other.
Begin with the lowest denomination, and take the number in the lower line from the one standing over: proceed in the same way with all the denominations.
Should the number in the upper line be less than the one standing under it, suppose as many units to be added to the upper number as will make a unit of the next higher denomination, remembering to diminish the number in the next place in the upper line by 1.
PROOF.—The same as in Simple Subtraction.
QUESTIONS FOR PRACTICE.
lb. oz. pwt. gr.
lb. oz. pwt. gti Borr. 149 10 8 791 9 8 1 440 5 15 20 27 8 12 10 Paid
86 12 4 197 16 4 2 60 8 19 12 19 4 16 19
AVOIRDUPOIS WEIGHT. lb.
d. h. m.
to. cwt. gr. lb. oz. ds. 84 10 8 9 11 3 19 4 11 76 14 9 3 12 1 20 9 T
WINE MEASURE. yd ft. in. deg. mi. fur. rd. st. in. gal. qu. pt. gs.
hhd. gal. qt. pt. 25 2 10 36 40 3 22 8 7 48 1 0
63 36 3 1 16 1 11 17 45 1 37 9 3 24 3 1 0 59 42 3
A man sold a piece of land A person, having 624 yards for £735 11s. 6d., and receiv- 3qrs. of cloth, sold at one time, ed at one time £195 133. 11d., 247yds. 2qrs., and at another, and at another, £61 53.; how 114yds. lqr. ; how much has much remains due ?
he left? Ans. 263 yds. Ans. £478 12s. 70.
152. In computing interest, the month is commonly reckoned 30 days, and the year 12 months. (145) In working the following questions, in place of the months, write the numbers of the months. (137)
A note was on interest from How long was that note on Dec. 29, 1825, till June 22, interest, which was given, 1826, 1828 ; what was the length of January 3, and paid August 1, time?
of the same year? years. mo. days.
Ans. 6m. 28d. 1828
5 22 1825 11 29
How long from 1822, April
21, to 1826, March 15? 2 5 23 Ans.
Ans. 3yr. 10mo. 24d.
0. Multiplication and Division.
163. 1. What will 6lb. of coffee 154. 1. If hlb, of coffee cost 9s. cost at ls. 68. 3qr. per pound ? 4d. 2qr., how much is that per lb. ? The cost of 6lb, is
If we divide the &. d. gr. evidently times
s. d. qr.
price of 6lb. into 6 1 6 3 the cost of llb. ; we 6)9 4' 2(1s. equal parts, one of 6 therefore multiply
those parts must
be the price of llb. by
the price of 1]b. To Ayes. 9 4 2 6; thus, 6 times 3yrs. 3
do this we first seek are 18qr.4d. 2qr., 12
how many times 6 ja of which we write down the 2qr.,
Is., and write ls. for and reserve the 4d. to be joined 6) 10(6d. the quotient. We with the pence. We then say
then ' multiply.. and times 6d. are 36d., and 4d. reserved
subtract as in Simple are 400.3s. 4d., of which we write
Division. We ther down the 4d., and reserve the 3s. to
multiply the remainbe joined with the shillings. Lastly,
der, 3s., by 12, adding we say 6 times Is. are 6s., and 35. 6)18(3qr. the 4d. '(139), and direserved are 9s., which we write 18
vide the sum 40. by down, and the work is done.
6, which gives 6d. for
a quotient, and 4d. 2. What will 47 yards of cloth remain, which reduced to farthings, cost at 17s. 9d. per yard ?
and the 2qrs. added, make 18qrs. We first multiply | These divided by 6, give 3qrs. for d. 9d. by 47, and di- the quotient. Thus we find the price 17 9 viding the product of isb. to.he 1s. Od. 3qrs. 47 423d. by 12, find 2. If 47 yards of cloth cost £AI
35s. 3d. to be the 14s. 3d., what is that per yard ? 1214238. cost of 47yd. at 9d.
Hore we divide Again we multiply £ s. d. the whole price by 358.3d. 17s. by 47, and 47)41 14 3(£0 the whole quantity, 119 write the partia!
as before. As 47 68 products, which
is not contained in are shillings, under 47)834s.(17s. the pounds, 210)834s. the 35%. These ad
place a cipher in ded together make
ihe quotient and A. £41 14s. 3d. 834s., which divid
reduce the pounds ed by 20, give 841 329
lo shillings, adding 148., and bringing down the 3d., we
the 14s. Dividing have £41 14s. 3d. for the whole cost.
35. 831s. by 47, we This method will prevent the neces
get 17s. in the quor sity of dividing this rule into a varie:
lient. The remainty of cases.
der, 358., reciuc. By comparing the corresponding 35
ed to pence, and examples in the two columiis, it
the 3d. added, give will be seen that they mutually 47)123(9d. 423d., wbichdi. prove each other, and this arrange- 423 vided by 47, give ment prevents the necessity of in
9d. in the quotient. serting the answers under the ques.
Thus we find the tions, they being found in the adja.
price of one yard cout questions.
to be 178. 9.
COMPOUND MULTIPLICA- COMPOUND DIVISION
156. Is the method of sepa155. Is the method of find- rating a compound number ining the amount of a compound to any proposed number of number by repeating it a pro- equal parts (44). posed number of times (43).
158. Write the numbers as RULE.
in Simple Division, and divide 157.
Write the multiplier the several terms of the diviunder the lowest denomination dend successively by the diviof the multiplicand. Reserve Should the first term of from each product as many the dividend be less than the units as may be had of the divisor, reduce it to the next next higher denomination, and lower denomination, adding the write down the excess, adding number of the lower denomithe number reserved to the nation. Do the same with the next product.
several remainders. NOTE. This rule is susceptible
NOTE.-This rule is susceptible of the same contractions as Simple of the same contractions as Simple Multiplication.
QUESTIONS FOR PRACTICE.
3. What will 6 cows cost at 3. If 6 cows cost £26, how £4 6s. 8d. apiece?
much is that apiece? 4. What will 9cwt. of cheese 4. If 9cwt. of cheese cost cost at £1 11s. 5d. per cwt? £14 2s. 9d. how much is that
5. What will 28 yards of per cwt. ? broadcloth cost at 198. 4d. per 5. If 28yds. of broadcloth
cost £27 1s. 4d. what is that a 6. What will 96 quarters of yard ? rye cost at £1 3s. 4d. a qr. ? 6. If 96qrs of rye cost £112,
7. What will 47 yards of how much is ihat a qr. ? cloth cost at 178. 9d. a yard ? 7. If 47yds. of cloth cost
8. How many yards in 17 £41 14s. 38. what is that a pieces, each containing 29yds. yard ? 3qrs.?
8. In505 yd. 3qr. how many 9. What will 94 pair of pieces of 29yd. 3qr. each? stockings cost' at 12s. 20. a 9. If 94 pair of stockings pair?
cost £57 33. 8d. what is that a 10. What will 512 bushels pair? of wheat cost at 58. 10d. a 10. If 512 bushels of wheat bushel ?
cost £149 6s. 8d. what is that 11. If a span of horses eat 2 a bushel ? bu. 3 pks. of oats in one week, 11. If a span of horses eal bow many will they eat in 25 68bu. Bpk. of oats in 25 weeko woeks?
how much is that a week?