EXAMPLES. S. 'di What is the sum total of 471. 13s. 13 6 60. 191. 28. 9fd.--146. 10s. 111d. 19 2 91 and 121. 9s. 12d.? Thus 14 10 11 12 9 Answer, £. 93 16 43 (2) S. d 4. S. d. gr. . 1 13 11 84 17 5 3 30 11 4" 2 13 10 2 75 13 4 15 10 9 1 10 17 50 17 8 2 1 0 1 1 8 8 7 20 10 '10 1 3 98 S 3 3 16 5 0 4 6 3 1 d. 1 11. Find the amount of the following , £. $. sums, viz. 421. 13s. 5d.-11l. 10s.-41. 175. 8d.-131. Os. 74.-19s. 41.-271 and 15l. 63. 12. Add 3041. 5s. and Ojd.--341. 19s. 70–71. 18s. 5d. _2471. Os. 11d.-19s. 6d. 1gr. and 45l. together. Ans. £640 3s. 5jd. 13. Find the sum total of 141. 19s. 60.-111.4s. 9d. 251. 10s.-41. Os. 60.-31. 55. 8.-19s. 6d. and Os. 6d. Ans: £60) Os: 5d. 14. Find the amount of the following sums, viz. Forty pounds, nine shillings, d. Sixty-four pounds and nine pence, Ninety-five pounds, nineteen shillings, Seventeen shillings and 41d. Ars. £. 2016 1 .5. How much is the sum of Ans. £. 10 Os. 101d. 16. Bought a quantity of goods for 125l. 10s. paid for truckage forty-five shillings, for freight seventy-nine shillings and six pence, for duties thirty-five shillings and ten pence, and my expences were fifty-three shillings and , mine pence; what did the goods stand ine in ? Ans. £a: 136 4s, 1d. 17. Six men took a prize, and having divided it equally umongst them, each man shared two hundred and forty sounds, thirteen shillings and seven pence; how much noney did the whole prize amčunt to? Ans, f. 1444 is, 6d. 如B48640 2. TROY WEIGHT. lþ. oz. pwt. gr. lb. oz. pwt. gr. 11 19 23 8. 11 19 4 16 21 6 10 16 { 8 8 19 14 7 8 17 21 6 9 14 17 6 3 25 4 7 10 7 9 7 14 17 7 11 7 9.13 10. 12 Эgr. 5 Эgr. 9 1 17 § 2 9 6 1 17 O 16 5 12 6 1 10 k. APOTHEOARIES WEIGHT. ѣ Z 5 9 gr. 10 7 2 19 12 11 6 1 6 3 0 12 4 9 70 12 7 6 1 7 9 10 1 2 16 9 5 2 4 8 1 2 19 6 1 0 16 9 0 1 9 3 2 19 4 9 1 6 12 10 5. CLOTH MEASURE E. F. gr. na. yd. gr. na. 44 3 2 84 2 1 18 9. LAND OR SQUARE MEASURF.. acres.roods.rods. acres.roods. rods. soft. sq.in. 478 3 31 856 2 5 136 816 17 6 129 49 1 27 9 1 39 8 134 s S4 3 00 U 145 9 3 37 0 3-4 00 65 COMPOUND SUBTRACTION, TEACHES to find the difference, inequality or excess, between any two sums of diverse denominations. RULE. Place those numbers under each other, which are of the same denomination, the less being nelow the greater; begin with the least denomination, and if it exceed the figure over it, borrow as many units as make one of the next greater; subtract it therefrom; and to the difference add the upper figure, remembering always to add one to the next superior denomination for that which you borrowed! |