The engineers' manual of the Local marine examinations |
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Page 135
... lead 35 × 10 feet at 6 lb. 11 oz , to the foot , and its cost at 3 d . per foot . 16. The weight of 3 miles of iron pipes 189 lbs . per foot run , and the cost at 8s . rod . per cwt . 17 . 12 tons 13 cwt . 3 qrs . 4 lbs . copper at 958 ...
... lead 35 × 10 feet at 6 lb. 11 oz , to the foot , and its cost at 3 d . per foot . 16. The weight of 3 miles of iron pipes 189 lbs . per foot run , and the cost at 8s . rod . per cwt . 17 . 12 tons 13 cwt . 3 qrs . 4 lbs . copper at 958 ...
Page 139
... lead 35 × 10 feet at 6 lb. 11 oz , to the foot , and its cost at 3 d . per foot . 16. The weight of 3 miles of iron pipes 189 lbs . per foot run , and the cost at 8s . rod . per cwt . 17 . 12 tons 13 cwt . 3 qrs . 4 lbs . copper at 958 ...
... lead 35 × 10 feet at 6 lb. 11 oz , to the foot , and its cost at 3 d . per foot . 16. The weight of 3 miles of iron pipes 189 lbs . per foot run , and the cost at 8s . rod . per cwt . 17 . 12 tons 13 cwt . 3 qrs . 4 lbs . copper at 958 ...
Page 151
... Lead weighs 11 times , and platinum 21 times , as much as water ; what weight of platinum will be equal in bulk to 112 lbs . of lead ? 48. A watch which gains uniformly tells the true time once in every 200 days ; how much does it gain ...
... Lead weighs 11 times , and platinum 21 times , as much as water ; what weight of platinum will be equal in bulk to 112 lbs . of lead ? 48. A watch which gains uniformly tells the true time once in every 200 days ; how much does it gain ...
Page 196
... lead in a pipe of an inch - and - a - quarter bore , which weighs 14 lbs . per yard in length , the cubic foot of lead weighing 11325 oz8 . 32. A cable which is 3 feet long and 9 inches in compass weighs 22 lbs .: required the weight of ...
... lead in a pipe of an inch - and - a - quarter bore , which weighs 14 lbs . per yard in length , the cubic foot of lead weighing 11325 oz8 . 32. A cable which is 3 feet long and 9 inches in compass weighs 22 lbs .: required the weight of ...
Page 200
... lead is in the form of a pyramid , on a square base whose side is 5 in . , the height of the pyramid being 6 in .: required the weight . 5. What is the weight of a round rod of iron 1 in . in diameter and 11 ft . long ? 6. Required the ...
... lead is in the form of a pyramid , on a square base whose side is 5 in . , the height of the pyramid being 6 in .: required the weight . 5. What is the weight of a round rod of iron 1 in . in diameter and 11 ft . long ? 6. Required the ...
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The Engineers' Manual of the Local Marine Examinations Thomas Liddell Ainsley No preview available - 2015 |
Common terms and phrases
air-pump Answer area of valve atmospheric line boiler bolts bottom cent centre circumference coal condenser contains cost crank cubic feet cubic foot cubic inches cyphers decimal denominator diagram distance divide dividend divisor effective pressure engine equal EXAMINATION PAPER-No EXAMPLES FOR PRACTICE exhaust figure fraction gallons heat high pressure horse-power hundred inches diameter inches of mercury indicator indicator diagram length of stroke lever mean effective pressure miles multiplicand multiply piston pitch plates port pounds pressure cylinder pressure of steam pressure per square pump quantity quotient ratio of expansion reduce remainder revolutions per minute rivets RULE safety-valve screw seams shaft side slide-valve specific gravity square feet square inch stays steam is cut subtract surface surface condenser tank temperature thickness thousand throughout the stroke tons total pressure tube vacuum vulgar fraction weight whole numbers
Popular passages
Page 42 - An Improper Fraction is one whose numerator is equal to or greater than its denominator ; as, f , -J.
Page 63 - Thus, reducing the two fractions to a common denominator, we multiply the numerator of the dividend by the denominator of the divisor, and the numerator of. the divisor by the denominator of the dividend ; (Art.
Page 139 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Page 56 - It is however impossible to find such a fraction unless all the given fractions be first expressed with a common denominator : for, since the denominator of a fraction expresses the number of equal parts into which the unit is divided, it follows that in two fractions which have not a common denominator the unit is not divided into the same number of equal parts : therefore in endeavouring to...
Page 239 - ... stroke have been performed, and the steam be at the same time throttled in the steam pipe, the full pressure of the steam within the cylinder cannot be maintained except near the beginning of the stroke where the piston travels slowly ; for as the speed of the piston increases, the pressure necessarily subsides, until the piston approaches the other end of the cylinder, where the pressure would rise again but that the operation of the lap on the valve by this time has had the effect of closing...
Page 239 - ... on the exhausting side, the port before the piston will be closed before that behind it is opened ; and the interval between the closing of the one and the opening of the other, will depend on the quantity of lap on the exhausting side of the valve.