Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by Numbers are Analytically Explained and Synthetically Applied |
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Page 38
... mills make one dollar ; how many in 25000 mills ? in 845000 ? 8. How many dollars in 6487 mills ? 9. How many dollars in 42863 mills ? in 96842378 mills ? Ans . 426100 dollars in 4000 mills ? Ans . 6487 dollars . 1000 in 368456 mills ...
... mills make one dollar ; how many in 25000 mills ? in 845000 ? 8. How many dollars in 6487 mills ? 9. How many dollars in 42863 mills ? in 96842378 mills ? Ans . 426100 dollars in 4000 mills ? Ans . 6487 dollars . 1000 in 368456 mills ...
Page 44
... mills , is a compound number ; so 4 years 6 months and 3 days , 46 pounds 7 shillings and 6 pence , are compound ... mills . 10 mills 10 cents , 10 dimes , 10 dollars , 100 mills , ) 100 cents 100 dimes are equal to · • 1 cent . = 1 dime ...
... mills , is a compound number ; so 4 years 6 months and 3 days , 46 pounds 7 shillings and 6 pence , are compound ... mills . 10 mills 10 cents , 10 dimes , 10 dollars , 100 mills , ) 100 cents 100 dimes are equal to · • 1 cent . = 1 dime ...
Page 45
... mills make a cent , and con- sequently the mills never exceed 9 , and are always expressed by a single figure . Only one place , therefore , is appropriated to mills , that is , the place immediately following cents , or the third place ...
... mills make a cent , and con- sequently the mills never exceed 9 , and are always expressed by a single figure . Only one place , therefore , is appropriated to mills , that is , the place immediately following cents , or the third place ...
Page 46
... mills ? 8000 mills ? in 3000 mills ? in 846732 mills ? ir This changing one kind of money , & c . into another kind , without altering the value , is called REDUCTION . As there are 10 mills in one cent , it is plain that cents are ...
... mills ? 8000 mills ? in 3000 mills ? in 846732 mills ? ir This changing one kind of money , & c . into another kind , without altering the value , is called REDUCTION . As there are 10 mills in one cent , it is plain that cents are ...
Page 47
... mills . 2125 mills . or , 2625 mills = $ 2'625 Ans . OPERATION . $ 4'75 $ 2'125 $ 2'625 , Ans . 8. A man bought a cow for eighteen dollars , and sold her again for twenty - one dollars thirty - seven and a half cents ; how much did he ...
... mills . 2125 mills . or , 2625 mills = $ 2'625 Ans . OPERATION . $ 4'75 $ 2'125 $ 2'625 , Ans . 8. A man bought a cow for eighteen dollars , and sold her again for twenty - one dollars thirty - seven and a half cents ; how much did he ...
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Common terms and phrases
12 cents acres amount annexed annuity answer apples arithmetical series bushels called ciphers common difference composite number compound interest compound numbers contained cord feet cows cube root cubic decimal fractions diameter divided dividend division divisor dollars equal EXAMPLES FOR PRACTICE factors farthings federal money foot gain gallons given number greatest common divisor Hence hogshead horse hundred hundredths improper fraction inches last term least common multiple length less number measure miles mills minuend minutes mixed number months multiplicand multiply Note number of terms OPERATION oranges ounce paid pence pints pounds present worth principal proportion pupil quantity quarts quotient rate per cent ratio receive Reduce remainder right hand figure rule shillings side simple numbers sold solid feet square root subtraction subtrahend tens thousandths units vulgar fractions weight whole number write yards of cloth
Popular passages
Page 90 - Divide the denominator by the whole number, when it can be done without a remainder ; otherwise, multiply the numerator by it, and under the product write the denominator, which may then be reduced to a whole or mixed number.
Page 2 - BBOWN, of the said district, hath deposited in this office the title of a book, the right whereof he claims as author, in the words following, to wit : " Sertorius : or, the Roman Patriot.
Page 95 - Prom' the very process of dividing each of the parts, that is, of increasing the denominators by multiplying them, it follows, that each denominator must be & factor of the common denominator ; now, multiplying all the denominators together will evidently produce such a number. Hence, To reduce fractions of different denominators to equivalent fractions having...
Page 139 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Page 112 - 03, the same as before. IT 73. The foregoing examples and remarks are sufficient to establish the following RULE. In the division of decimal fractions, divide as in whole numbers, and from the right hand of the quotient point off...
Page 124 - The rate of interest upon the loan or forbearance of any money, goods or things in action...
Page 83 - Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain.
Page 142 - This may be done, provided the terms be so placed, that the product of the extremes shall be equal to that of the means. 4. If 3 men perform a certain piece of work in 10 days, how long will it take 6 men to do the same ? The number of days in which 6 men will do the work being the term sought, the.
Page 166 - Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Page 63 - Thirty days hath September, April, June, and November, February twenty-eight alone ; All the rest have thirty-one.