 | Robert Simson - Trigonometry - 1762 - 488 pages
...FB; for the fame reafon CF is equal to FD. and becaufe AD is equal to BC, and AF to FB, the two fides FA, AD are equal to the two FB, BC, each to each ; and the bafe DF was proved equal to the bafe FC ; therefore the angle FAD is eeq'.ial d to the angle FBC. agam,... | |
 | Robert Simson - Trigonometry - 1775 - 534 pages
...ABC, and the whole angle DBA is eq'ualc to the whole FBC ; and becaufe the two fides AB, BD c •- Ax. are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore the bafe AD is eqwlftothe bafe FC, and the triangle ABD... | |
 | Euclid - Geometry - 1776 - 318 pages
...FD is equal to FC $ but FA, AD, are proved equal to FB, BC, each to each ; and the bafe FD equal to FC ; therefore the angle FAD is equal to the angle FBC d. Again, becaufe FA, AG, are proved equal to FB, d 8. i, BH, each to each, and the angle FAG equal to FBH ;... | |
 | Euclid - 1781 - 552 pages
...for the fame reafon, CF is equal to FD : And becaufe AI? is equal to BC, and AF to FB, the two fides FA, AD are equal to the two FB, BC, each to each ; and the bafe DF was proved equal to the bafe FC ; therefore the angle FAD is equal d to the angle FBC : Again,... | |
 | Alexander Ingram - Trigonometry - 1799 - 374 pages
...ARC, e s. Ax. and tne whole angle DBA is equal e to the whole FBC ; and becaufe the two fides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; f 4. i. therefore the bafe AD is equal i to the bafe FC, and the... | |
 | Robert Simson - Trigonometry - 1804 - 530 pages
...; for the fame reafon CF is equal to FD. and becaufe AD is equal to BC, and AF to FB, the two fides FA, AD are equal to the two FB, BC, each to each; and the bafe DF was proved equal to the bafe FC ; therefore the angle FAD is equal d to the angle FBC. again,... | |
 | John Playfair, Euclid - Circle-squaring - 1804 - 468 pages
...angle ABC, the whole angle DBA will be equal e to the whole FBC ; and becaufe the two fides AB, BD, are equal to the two FB, BC, each to each, and the angle DBA equal to tho the angle FBC, therefors the bafe AD is equal f te the bafe Book I. FC, and... | |
 | Robert Simson - Trigonometry - 1806 - 546 pages
...ABC, and the whole angle DBA is equal « to the whole FBC ; and e 2. Ax. because the two sides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to. the angle FBC ; therefore the base AD is equal f to the base FC, and the trian-... | |
 | Euclid - Geometry - 1810 - 554 pages
...them, the base AF,is^-*^^s^ equal* to the base FB; for the same reason, CF is equal to FD: b 4. 1. and because AD is equal to BC, and AF to FB, the two sides FA, A Dare equal to the two FD, BC, each to each; and the base DF was proved equal to the base FC; therefore... | |
 | Euclides - 1814 - 560 pages
...EB, and FE common and at Boo* right angles to them, the base AF is equal b to the base FB ; " s ^ v for the same reason, CF is equal to FD : And because AD * 4 ' 1is equal to BC, and AF to FB, the two sides FA, AD are equal to the two FB, BC, each to each... | |
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FB ; (i. 4.) for the same reason, CF is equal to FD : and because AD is equal to BC, and AF to FB, the two sides FA, AD are equal to the two FB, BC, each to each ; and the base DF was proved equal to the base FC ; therefore the angle FAD is equal to the... 
