A Practical Arithmetic |
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Page 40
... cubic feet in a cord . cubic feet are there in 187 cords of wood ? How many 11. A bushel of corn weighs 56 pounds . How many pounds will 625 bushels weigh ? 12. How many oranges are there in 47 boxes if each box contains 189 oranges ...
... cubic feet in a cord . cubic feet are there in 187 cords of wood ? How many 11. A bushel of corn weighs 56 pounds . How many pounds will 625 bushels weigh ? 12. How many oranges are there in 47 boxes if each box contains 189 oranges ...
Page 41
... cubic feet , how many cubic feet will there be in 139 tons ? 23. A cubic foot of hard coal weighs 84 pounds . How many pounds will 27 cubic feet weigh ? 24. A cubic foot of silver weighs 656 pounds . How many pounds will 16 cubic feet ...
... cubic feet , how many cubic feet will there be in 139 tons ? 23. A cubic foot of hard coal weighs 84 pounds . How many pounds will 27 cubic feet weigh ? 24. A cubic foot of silver weighs 656 pounds . How many pounds will 16 cubic feet ...
Page 54
... cubic inches in 39 gallons . How many cubic inches are there in one gallon ? 11. There are 13,600 square rods in 85 acres . many square rods are there in one acre ? 12. There are 47,520 yards in 27 miles . yards are there in one mile ...
... cubic inches in 39 gallons . How many cubic inches are there in one gallon ? 11. There are 13,600 square rods in 85 acres . many square rods are there in one acre ? 12. There are 47,520 yards in 27 miles . yards are there in one mile ...
Page 55
... cubic foot of solid ice weighs 58 pounds . How many cubic feet of ice are there in a freight car that contains 29,116 pounds of ice ? 22. If the earth in its revolution round the sun moves 1,641,600 miles a day , how far does it move in ...
... cubic foot of solid ice weighs 58 pounds . How many cubic feet of ice are there in a freight car that contains 29,116 pounds of ice ? 22. If the earth in its revolution round the sun moves 1,641,600 miles a day , how far does it move in ...
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Common terms and phrases
acres annex annuity barrels Benjamin Parker bought bushels called cents a pound circumference cistern coal commission common fraction compound interest contains cords cube root cubic feet cubic foot cubic meter decimal point denominator diameter discount dividend divisor dollars equal Exercise expressed feet board measure figures Find the amount Find the cost Find the interest Find the number Find the product flour frustum gallons given number Hence hundred hundredths improper fraction inches integral number least common multiple long tons longitude million minuend mixed number multiplicand Multiply number of feet ounces paid payment pints quarts quotient ratio remainder short ton sold SOLUTION square meter square miles square root subtract subtrahend tens term thousand tons units varas weighs wheat whole number wide worth write WRITTEN yards
Popular passages
Page 149 - TIME 60 seconds (sec.) = 1 minute (min.) 60 minutes = 1 hour (hr.) 24 hours = 1 day (da.) 7 days = 1 week (wk.) 365 days = 1 common year (yr.) 366 days . = 1 leap year (1.
Page 148 - Dry Measure 2 pints (pt.) =1 quart (qt.) 8 quarts = 1 peck (pk.) 4 pecks = 1 bushel (bu.) 2150.42 cu.
Page 250 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 283 - Thirty days after sight of this first of exchange (second and third of the same tenor and date unpaid...
Page 142 - LIQUID MEASURE 4 gills (gi.) = 1 pint (pt.) 2 pints — 1 quart (qt...
Page 262 - ... is equal to the square root of the difference of the squares of the hypotenuse and the other side.
Page 241 - That is, in any proportion either extreme is equal to the product of the means divided by the other extreme ; and either mean is equal to the product of the extremes divided by the other mean.
Page 172 - PERIPHERY of a circle is its entire bounding line ; or it is a curved line, all points of which are equally distant from a point within called the centre.
Page 101 - To reduce a mixed number to an improper fraction. Multiply the whole number by the denominator of the fraction, and to the product add the given numerator.
Page 254 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until all the periods are brought down. NOTE.