 | Edmund Wingate - Arithmetic - 1751 - 401 pages
...'|° = 30. 299. Hence if it be required to multiply an integer by a Fraction, multiply the integer by the Numerator of the Fraction and divide the product by the Denominator. For Example, the product of 48 by \ is = 6X5 = 30. That the methods above directed are true, may be... | |
 | Thomas Hodson - Education - 1806
...number in the upper line. Then multiply the laft number, thus found by the abfolute number (6)t in the numerator of the fraction, and divide the product by the denominator; then the remainder will be the true value of x required, provided the number of terms in the upper... | |
 | L. I. M. Chevigné - Education - 1807
...write . 5 We shall here observe, that to multiply a whole number by a fraction, we must multiply that number by the numerator of the fraction, and divide the product by the denominator of said fraction. Let us now return to the question proposed ; I say now, that it was not 3 I had to... | |
 | Osgood Carleton - Arithmetic - 1810 - 251 pages
...то SIMPLE MULTIPLICATION. CASE I. When the multiplier is a fraction, as •§, -J, Sec. multiply by the numerator of the fraction, and divide the product by the denominator ; the quotient will be the true product : If the numerator be 1, divide by the denominator only, as... | |
 | Thomas Keith - Navigation - 1810 - 420 pages
..."03859. PROPOSITION XI. t (P) To find the value of a quantity having a vulgar fraction for it; exponent. RULE. Multiply the logarithm of the given number by the numerator of the exponent, and divide the product by the denominator ; the quotient will be the logarithm of the quantity... | |
 | John Bonnycastle - Algebra - 1813
...be the root required. But if it be a compound root, or one that consists both of a root and a power, multiply the logarithm of the given number by the numerator of the index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
 | John Bonnycastle - Algebra - 1818 - 260 pages
...be the root required. But if it be a compound root, or one that consists both of a root and a power, multiply the logarithm of the given number by the numerator of the index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
 | Beriah Stevens - Arithmetic - 1822 - 423 pages
...|X5|3 = i||°=H3||s.=£5 13s. 1(M. or, without reducing, you may DTiultiply the given multiplicand by the numerator of the fraction, and divide the product by the denominator. EXERCISES. 1. Multiply 4 by TiT. Product 44. 2. Multiply 7| by | . Product 6|| . 3. Multiply 8| by... | |
 | John Bonnycastle - Algebra - 1825 - 312 pages
...be the root required. But if it he a compound root, or one that consists both of a root and a power, multiply the logarithm of the given number by the numerator of the index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
 | Thomas Keith - Navigation - 1826 - 442 pages
...'03859. PROPOSITION XI. (P) Toßndthe value of a quantity having a vidgai- fraction far its exponent. RULE. Multiply the logarithm of the given number by the numerator of the exponent, and divide the product by the denominator ; the qwotient will be the logarithm of the quantity... | |
| |