| Edmund Wingate - Arithmetic - 1751 - 401 pages
...'|° = 30. 299. Hence if it be required to multiply an integer by a Fraction, multiply the integer **by the Numerator of the Fraction and divide the product by the Denominator.** For Example, the product of 48 by \ is = 6X5 = 30. That the methods above directed are true, may be... | |
| Thomas Hodson - Education - 1806
...number in the upper line. Then multiply the laft number, thus found by the abfolute number (6)t in **the numerator of the fraction, and divide the product by the denominator;** then the remainder will be the true value of x required, provided the number of terms in the upper... | |
| L. I. M. Chevigné - Education - 1807
...write . 5 We shall here observe, that to multiply a whole number by a fraction, we must multiply that **number by the numerator of the fraction, and divide the product by the denominator** of said fraction. Let us now return to the question proposed ; I say now, that it was not 3 I had to... | |
| Osgood Carleton - Arithmetic - 1810 - 251 pages
...то SIMPLE MULTIPLICATION. CASE I. When the multiplier is a fraction, as •§, -J, Sec. multiply **by the numerator of the fraction, and divide the product by the denominator** ; the quotient will be the true product : If the numerator be 1, divide by the denominator only, as... | |
| Thomas Keith - Navigation - 1810 - 420 pages
..."03859. PROPOSITION XI. t (P) To find the value of a quantity having a vulgar fraction for it; exponent. **RULE. Multiply the logarithm of the given number by the numerator of the** exponent, and divide the product by the denominator ; the quotient will be the logarithm of the quantity... | |
| John Bonnycastle - Algebra - 1813
...be the root required. But if it be a compound root, or one that consists both of a root and a power, **multiply the logarithm of the given number by the numerator of the** index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
| John Bonnycastle - Algebra - 1818 - 260 pages
...be the root required. But if it be a compound root, or one that consists both of a root and a power, **multiply the logarithm of the given number by the numerator of the** index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
| Beriah Stevens - Arithmetic - 1822 - 423 pages
...|X5|3 = i||°=H3||s.=£5 13s. 1(M. or, without reducing, you may DTiultiply the given multiplicand **by the numerator of the fraction, and divide the product by the denominator.** EXERCISES. 1. Multiply 4 by TiT. Product 44. 2. Multiply 7| by | . Product 6|| . 3. Multiply 8| by... | |
| John Bonnycastle - Algebra - 1825 - 312 pages
...be the root required. But if it he a compound root, or one that consists both of a root and a power, **multiply the logarithm of the given number by the numerator of the** index, and divide the product by the denominator, for the logarithm of the root sought. Observing,... | |
| Thomas Keith - Navigation - 1826 - 442 pages
...'03859. PROPOSITION XI. (P) Toßndthe value of a quantity having a vidgai- fraction far its exponent. **RULE. Multiply the logarithm of the given number by the numerator of the** exponent, and divide the product by the denominator ; the qwotient will be the logarithm of the quantity... | |
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