121. When the divisor is a composite number. RULE. Divide the given compound number by one of the component parts, and that quotient by the other, the last quotient will be the answer, when there are only 2 component parts; if there are more than two, divide successively by them all, and the last quotient will be the answer. To prove the operation, change the order of the divisors as in Art. 103. 72. Divide 371. 12s 5d. by 16, several ways. 78. Divide 197b. Ooz. 19dwt. 9gr. by 15. Quot. 1lb. 3oz. 5dwt. 7gr. 79. Divide 128tuns, 1hhd. 60gal. 3qt. by 27. 3hhd. 2gal. 1qt. Quot. 4tuns, 80. Divide 1185qr. 7bu. 2pk. Ogal. by 132. Quot. 8qr. 7bu. 3pk. Igal. 122. When the divisor consists of a number with ciphers to the right hand. RULE. Divide by the significant figures only, without regarding the ciphers, and from the highest denomination of the quotient, cut off by a small line as many of its right hand figures as there are ciphers in the divisor. Reduce these right hand figures to the next lower denomination, taking in the figures of the same denomination from the said quotient. Cut off from the right of this number as many figures as there are ciphers in the divisor, reduce these to the next lower denomination, cut off, &c. and proceed in this manner through all the denominations; the numbers on the left hand of the cutting off lines being placed in order will be the quotient required. 81. Divide 379211. 2s. Sd.4 by 9000. OPERATION. L. S. d. 9)37921 2 84( 4213 9 20 4 269 12 3/230 4 01921 24 Explanation. I first divide by 9, neglecting the ciphers; then, because there are 3 ciphers, I cut off 3 figures, viz. 213, from the left of the pounds; this number I reduce to shillings, taking in the 9; from the shillings in like manner I cut off 3 figures, viz. 269, which I reduce into pence, taking in the 2; from the result I cut off 230, which I reduce into farthings, taking in the 1; and cut off 921, which is the remainder, and the left hand numbers cut off placed in order constitute the quotient. Quotient 41. 4s. 3d. 921 rem. |