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Explanation.

Here the highest place of the multiplier is thousands; I therefore multiply by 10 x 10 x 10 for 1000: I next multiply this product by 2 for 2000: I next multiply the product of 100 (or 10 X 10) by 3 for the product of 300; this I place under the former: then I multiply the product of 10 by 4, which gives the product of 40; this I place under the others: I next multiply the top line by 5, and place the product under the former ones. Lastly, I add the 40 four products together for the an5 swer.

0 =prod. by 2000

300

84=prod. by 2345

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Prod. 6981. 2s.
Prod. 3431. 18s. 7d.
Prod. 2571. 12s. 4d.

105. Multiply 4l. 9s. 6d. by 156. 106. Multiply 17s. 5d. by 394. 107. Multiply 1s. 8d. by 3016. 108. Multiply lewt. 2qr. 3lb. by 4321. 27lb.

Prod. 6597cwt. Oqr.

109. Multiply 1tun, 3hhd. 2gal. 1qt. by 980. Prod. 1723 tuns, 3hhd.

106. PROMISCUOUS EXAMPLES FOR PRACTICE.

110. Seven tailors received each 11. 4s. 9d. for a week's wages; what sum was sufficient to pay them? Ans. 8l. 13s. 3d. 111. What is the value of 16 cwt. of sugar, at 3l. 17s. 4d. per cwt. ? Ans. 611. 17s. 4d.

112. Bought 120 dozen of candles, at 11s. 6d. per dozen; what sum do they amount to? Ans. 691.

113. Sold 96 gallons of rum, at 11. 8s. 6d. per gallon; what sum will pay for the whole? Ans. 1361. 16s.

114. What is the worth of 17 yards of velvet, at ll. 3s. 1d.÷ per yard? Ans. 19l. 13s. 1d.

115. Required the weight of 1000 pieces of gold coin, each weighing 6dwts. 7gr. Ans. 26lb. 2oz. 11dwt. 16gr.

116. What is the weight of 19 chests of tea, each lcwt. Oqr. 14lb.? Ans. 21cwt. 1qr. 14lb.

117. To fill a cooler, there were put in 105 pails of liquor, each 3gal. 1qt. 1pt.; what quantity did the cooler hold? Ans. 6hhd. 30gal. 1qt. 1pt.

118. A bankrupt owes in all 24681. and can pay 15s. 6d. in the pound; what are his effects worth? Ans. 19171. 16s. 10. 119. A detachment, consisting of 3258 cavalry, being sent on a particular service, during which each horse ate 3bu. 3pk. 1gal. of oats; how many quarters did the whole detachment consume? Ans. 1578qr. 3pk.

COMPOUND DIVISION.

107. Compound Division teaches how to divide compound numbers by simple ones, that is, to divide a compound number into any assigned number of equal parts.

108. When the divisor does not exceed 12.

RULE. Place the divisor to the left hand of the dividend.

Divide the highest denomination of the dividend, and set the quotient under, as in simple Division. Reduce the remainder (if there is any) to the next inferior name, and add to it the number which is of the same name in the dividend. Divide, set down the quotient, and reduce the remainder to the next inferior name; proceed in this manner until you have divided all the denominations in the given dividend'.

The method of proof. Multiply the quotient by the divisor, and add in the remainder; the result will be like the dividend, if the work is right.

109. EXAMPLES IN MONEY.

1. Divide 13570l. 1s. 3d.4 by 6.

OPERATION.

L.

S. d.

6)13570 1 33(3 Quot. 2261 13 61 Proof 13570 1 33

Explanation.

The pounds are divided as in simple Division, (Art. 37. B.) after which there are 4 remaining; therefore I say, 4 pounds are 80 shillings and 1 are 81; sixes in 81 will go 13 times, and 3 over; put down 13, and reduce the 3 over into pence; thus, 3 shillings are 36 pence and 3 (in the dividend to add in) are 39; sixes in 39 will go 6 times, (to put down,) and 3 over: 3 pence are 12 farthings and 3 (in the dividend) are 15; sixes in 15 will go twice, (put down 2 or 1,) and 3 over. I multiply the quotient by 6, (Art. 91.) and the result is the proof.

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iTo divide a number consisting of several denominations by any simple number, is evidently no more than to divide the several parts of the former by the latter if any denomination be not exactly divisible, it is plain we must divide as much of it as will exactly divide, reduce the rest to the next lower denomination, and proceed as directed in the rule; whence, since every part of the dividend is divided, the several results collected will form the quotient.

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110. TROY WEIGHT.

26. Divide 235lb. 3oz. 2dwt. 12gr. by 7.

OPERATION.

lb. oz. dwt. gr. 7)235 3 2 12(5 Quot. 33 7 6 1 3 Proof 235 2 12

Explanation.

Having divided the pounds, there are 4 over; 1 therefore say, 4 pounds are 48 ounces and 3 are 51; sevens in 51 will go 7 times, and 2 over; put down 7; then 2 ounces are 40 dwts. and 2 are 42; sevens in 42 will go 6 times, and nothing over; put down 6, and there is nothing to carry;

lastly, sevens in 12 will go once, and 5 over; put down 1, and 5 to the right In the proof the 5 is taken in with the grains; the rest

hand for a remainder.

is obvious.

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th.

OPERATION.
339

8)137 1 2 1

gr.

10(6

17 1 5 0 137 1 2 1

18

10

Explanation.

After dividing the lbs., 1 remains; 1 pound is 12 ounces and 1 are 13; eights in 13 will go once, and 5 over; put down ; then 5 ounces are 40 drams and 2 are 42; eights in 42 will go 5 times, and 2 over; put down 5; then 2 drams are 6 scruples and 1 are 7; eights in 7 will not go; therefore put down 0; 7 scruples are 140 grains and 10 are 150; eights in 150 will go 18 times, and 6 òver.

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