Page images
PDF
[ocr errors]
[ocr errors][merged small][ocr errors][ocr errors][ocr errors][ocr errors][ocr errors][merged small][merged small]

Erplanation.

Here the highest place of the multiplier is thousands; -I therefore multiply by 10 x 10 x 10 for 1000: I next multiply this product by 2 for 2000: I next multiply the product of 100 (or 10 x 10) by 3 for the product of 300; this I place under the former: then I multiply the product of 10 by 4, which gives the product of 40; this I place under the others: I next multiply the top line by 5, and place the product under the former ones. Lastly, I add the four products together for the anSWer,

[ocr errors][ocr errors][ocr errors]
[merged small][ocr errors][ocr errors][merged small][ocr errors][merged small][merged small][merged small][ocr errors][ocr errors][ocr errors]
[ocr errors][merged small]

110. Seven tailors received each ll. 4s. 9d. for a week's wages; what sum was sufficient to pay them 2 Ans. 8l. 13s. 3d. 111. What is the value of 16 cwt. of sugar, at 31, 17s. 4d. per cwt. Ans. 611, 17's. 4d. 112. Bought 120 dozen of candles, at 11s. 6d. per dozen; what sum do they amount to ? Ans. 691. 113. Sold 96 gallons of rum, at ll. 8s. 6d. per gallon; what sum will pay for the whole Ans. 1361. 16s. 114. What is the worth of 17 yards of velvet, at ll. 3s. 1d.; per yard 2 Ans. 191. 13s. 1d.; 115. Required the weight of 1000 pieces of gold coin, each weighing 6dwts. 7 gr. Ans. 26lb. 202. 11dwt. 16gr. 116. What is the weight of 19 chests of tea, each lcut. Oqr. 14lb. ? Ans. 21cwt. 1gr. 14lb. 117. To fill a cooler, there were put in 105 pails of liquor, each 3gal. 1gt. 1pt.; what quantity did the cooler hold 2 Ans. 6hhd. 30gal. 1gt. 1pt. 118. A bankrupt owes in all 2468l. and can pay 15s. 6d. } in the pound; what are his effects worth Ans. 1917 l. 16s. 10. 119. A detachment, consisting of 3258 cavalry, being sent on a particular service, during which each horse ate 3bu. 3pk. Igal. of oats; how many quarters did the whole detachment consume 2 Ans. 1578qr. 3pk.

COMPOUND DIVISION.

107. Compound Division teaches how to divide compound numbers by simple ones, that is, to divide a compound number into any assigned number of equal parts. 108. When the divisor does not erceed 12. RULE. Place the divisor to the left hand of the dividend. Divide the highest denomination of the dividend, and set the quotient under, as in simple Division. Reduce the remainder (if there is any) to the next inferior name, and add to it the mumber which is of the same name in the dividend. Divide, set down the quotient, and reduce the remainder to the next inferior name; proceed in this manner until you have divided all the denominations in the given dividend'.

The method of proof. Multiply the quotient by the divisor, and add in the remainder; the result will be like the dividend, if the work is right.

[merged small][ocr errors]

OPERATIon. Erplanation. L. s. d. The pounds are divided as in simple 6) 13570 1 33 (3 Division, (Art. 37. B.) after which there - ----- are 4 remaining ; therefore I say, 4 pounds Quot. 2261 13 6; are 80 shillings and l are 8 l ; sixes in 81 - —H···s−1–H will go 13 times, and 3 over ; put down Proof _l:35.70 | 84 13, and reduce the 3 over into pence; thus, 3 shillings are 36 pence and 3 (in the dividend to add in) are 39; sixes in 39 will go 6 times, (to put down,) and 3 over: 3 pence are 12 farthings and 3 (in the dividend) are 15; sixes in 15 will go twice, (put down 2 or +,) and 3 over. I multiply the quotient by 6,

(Art. 91.) and the result is the proof.

[ocr errors]

i To divide a number consisting of several denominations by any simple number, is evidently no more than to divide the several parts of the former by the latter: if any denomination be not exactly divisible, it is plain we must divide as much of it as will exactly divide, reduce the rest to the next lower denomination, and proceed as directed in the rule; whence, since every part of the dividend is divided, the several results collected will form the quotient.

[ocr errors]
[ocr errors]
[ocr errors]

OPERATION. Erplanation. lb. oz. dwt. gr. Having divided the pounds, there are 4 7)235 3 2 12(5 over; 1 therefore say, 4 pounds are 48 - ounces and 3 are 5 i ; sevens in 51 will go Quot. 33 7 6 l 7 times, and 2 over; put down 7 ; then 2 —--- ounces are 40 dwt.s. and 2 are 42; sevens Proof 235 3 2 12 in 42 will go 6 times, and nothing over; put down 6, and there is nothing to carry; lastly, sevens in 12 will go once, and 5 over; put down 1, and 5 to the right

hand for a remainder. In the proof the 5 is taken in with the grains; the rest is obvious.

[ocr errors]

111. APOTHECARIES WEIGHT. 31 Divide 137th 13 23 19 logr. by 8.

[merged small][ocr errors][ocr errors]
« PreviousContinue »