Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks |
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Page 22
... purchased 29 yards of ribbon for 61 cents a yard , gave the merchant a 2 dollar bill ; how much change ought she to have received ? MISCELLANEOUS QUESTIONS . VIII . 1. A man bought 12 bushels of wheat for 30 dollars , and sold 9 bushels ...
... purchased 29 yards of ribbon for 61 cents a yard , gave the merchant a 2 dollar bill ; how much change ought she to have received ? MISCELLANEOUS QUESTIONS . VIII . 1. A man bought 12 bushels of wheat for 30 dollars , and sold 9 bushels ...
Page 25
... purchased a sloop together . A took of it , B. , C. and D , the rest , which cost him 100 dollars . What was D's part ? What did the other parts severally cost ? What did the whole sloop cost ? 54. The fifth part of an army was killed ...
... purchased a sloop together . A took of it , B. , C. and D , the rest , which cost him 100 dollars . What was D's part ? What did the other parts severally cost ? What did the whole sloop cost ? 54. The fifth part of an army was killed ...
Page 38
... purchased a ship for 25,000 dollars , and sold it for 3,715 dollars more than it cost him . What did he get for it ? A. 28,715 dollars . for 13,000 dollars , What did he give A. 14,750 dollars . 65. A gentleman sold a tract of wild land ...
... purchased a ship for 25,000 dollars , and sold it for 3,715 dollars more than it cost him . What did he get for it ? A. 28,715 dollars . for 13,000 dollars , What did he give A. 14,750 dollars . 65. A gentleman sold a tract of wild land ...
Page 40
... purchased a farm for 4,000 dollars , and paid 5 lollars as 66 earnest money . ' 991 How much did he still owe ? 4000 5 A. 3 9 9 5 Say 5 from 10 leaves 5 ; 1 to carry from 10 leaves 9 ; 1 to carry again from 10 leaves 9 ; 1 to carry from ...
... purchased a farm for 4,000 dollars , and paid 5 lollars as 66 earnest money . ' 991 How much did he still owe ? 4000 5 A. 3 9 9 5 Say 5 from 10 leaves 5 ; 1 to carry from 10 leaves 9 ; 1 to carry again from 10 leaves 9 ; 1 to carry from ...
Page 50
... purchased 1,250 acres of land for 2 dollars an acre ; 1,400 acres for 3 dollars an acre , and 3,000 acres for 4 dollars an acre . How much money had he left on his return ? A. 1,300 dollars . SIMPLE DIVISION . ' XXI . 1. A man having 28 ...
... purchased 1,250 acres of land for 2 dollars an acre ; 1,400 acres for 3 dollars an acre , and 3,000 acres for 4 dollars an acre . How much money had he left on his return ? A. 1,300 dollars . SIMPLE DIVISION . ' XXI . 1. A man having 28 ...
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Common terms and phrases
12 cents 50 cents acres amount angles annexing apiece barrels of flour bought breadth bushels called cent pieces ciphers circumference common divisor composite number compound interest compound number contain cows cube root cubic decimal denominator diameter difference discount Divide dividend Division dollars equal example excess factors farthings Federal money feet long Find the sum fraction frustrum gallons given number greater greatest common divisor Hence hogshead horses hundred improper fraction inches indorsed least common multiple length merchant miles million mills minuend mixed number months multiplicand Multiply ounces payment pence pints pounds present worth proportion purchase quadrillion quantity quarts quotient rate per cent ratio reckoning Reduce remainder Repeat the Table sell shillings sold solid feet square rods square root subtract subtrahend Suppose tens thousand TROY WEIGHT units vulgar fraction whole number yards of cloth
Popular passages
Page 242 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 115 - Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remains; the last divisor is the common measure.* 2. Divide both of the terms of the fraction by the common measure, aud the quotients will make the fraction required. * To find the greatest common measure...
Page 116 - Mnltiple of two or more numbers is the least number that can be divided by each of them without a remainder ; thus 30 is the least common multiple of 10 and 15.
Page 35 - This is no denial of the mathematical proposition that the whole is equal to the sum of all its parts...
Page 207 - The first term of a ratio is called the ANTECEDENT, and the second, the CONSEQUENT, and both together form a COUPLET, as 12 : 3.
Page 121 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 254 - Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1; the quotient will be the sum of the series required.
Page 215 - Lastly, multiply the third term by the continued product of the second terms, and divide the result by the continued product of the first terms, and the quotient will be the fourth term, or answer required.
Page 186 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced, add it to the principal, and deduct the payment from the sum total. If there be...
Page 277 - ... above the upper deck ; the breadth thereof at the broadest part above the main wales, half of which breadth shall be accounted the depth of such vessel, and...