## Military examinations. Mathematical examination papers, set at entrance to the Royal military college, Sandhurst, with answers, by W.F. Austin |

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Military Examinations. Mathematical Examination Papers, Set at Entrance to ... Sandhurst Roy Military Coll No preview available - 2015 |

### Common terms and phrases

acres altitude base centre circular measure circumference common Construct cosine cubic feet cubic foot decimal Define Describe a circle described determine diameter difference digits Divide divisible double drawn equal equilateral triangle explain express Extract the square field figure Find the area find the number formula four fraction given circle given log given points given straight line given triangle greater greatest half height hexagon hour inches included inscribed isosceles triangle least length less logarithms magnitudes MATHEMATICS mean miles Multiply parallel parallelograms pass perpendicular places produced proportional Prove prove the rule pyramid quantities radius ratio rectangle contained Reduce regular remainder respectively right angle segment semicircle sides similar Simplify sine Solve the equations sphere square root straight line subtending tangent touch units weighs whole line wide yards

### Popular passages

Page 44 - Radian is the angle subtended, at the centre of a circle, by an arc equal in length to the radius...

Page 24 - If from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, is equal to the square of the line which touches it.

Page 36 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.

Page 12 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.

Page 2 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.

Page 36 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.

Page 36 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.

Page 44 - ... cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.

Page 2 - ... the side subtending the obtuse angle, is greater than the squares of the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse...

Page 2 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.