A New and Complete System of Arithmetick: Composed for the Use of the Citizens of the United States |
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Results 1-5 of 99
Page 61
... EXAMPLES . 1. What is the least common multiple of 6 , 10 , 16 and 20 ? 16 20 * 5 ) 6 10 # 2 ) 6 2 16 * 2 ) 3 1 8 4 ... example : Thus , it is evident that 6X10 × 16 × 20 ( = 19200 ) may be divided by 6 , 10 , 16 and 20 , with- out a ...
... EXAMPLES . 1. What is the least common multiple of 6 , 10 , 16 and 20 ? 16 20 * 5 ) 6 10 # 2 ) 6 2 16 * 2 ) 3 1 8 4 ... example : Thus , it is evident that 6X10 × 16 × 20 ( = 19200 ) may be divided by 6 , 10 , 16 and 20 , with- out a ...
Page 63
... EXAMPLES . 1. Reduce 36 % to its equivalent improper fraction . 36 X8 + 5 Ans . 293 - Or , I multiply 36 by 8 , and adding the nu- merator 5 to the product , as I multiply , the sum 293 is the numerator of the fraction sought , and 8 ...
... EXAMPLES . 1. Reduce 36 % to its equivalent improper fraction . 36 X8 + 5 Ans . 293 - Or , I multiply 36 by 8 , and adding the nu- merator 5 to the product , as I multiply , the sum 293 is the numerator of the fraction sought , and 8 ...
Page 64
... EXAMPLES . 1. Reduce 23 to its equivalent whole , or mixed number . 8,293 ( 36 Ans . 24 53 48 5 Or , 293-293-8 = 36 as before . 2. Reduce 2163 to its equivalent whole , or mixed number . T7 Ans . 1274 . 3. Reduce 1241 ° to its ...
... EXAMPLES . 1. Reduce 23 to its equivalent whole , or mixed number . 8,293 ( 36 Ans . 24 53 48 5 Or , 293-293-8 = 36 as before . 2. Reduce 2163 to its equivalent whole , or mixed number . T7 Ans . 1274 . 3. Reduce 1241 ° to its ...
Page 65
... EXAMPLES . 1. Reduce , and to equivalent fractions , having a common denominator . 1x5x8-40 the new numerator for 2 × 4 × 8 = 64 the new numerator for 3 . 5 × 4X5 = 100 4x5x8-160 the common denominator . Therefore the new equivalent ...
... EXAMPLES . 1. Reduce , and to equivalent fractions , having a common denominator . 1x5x8-40 the new numerator for 2 × 4 × 8 = 64 the new numerator for 3 . 5 × 4X5 = 100 4x5x8-160 the common denominator . Therefore the new equivalent ...
Page 71
... EXAMPLES . 1. Add 74 , of , and 7 together . 15 First . 7 , of 3 , and 7-7 . Then the fractions are 39 , and ; therefore , 39x56x 1 = 2184 15X 5X 1 = 75 7x 5X56-1960 4219 3 ' 56 ' 5x56x1 = 280 2184 + 75 + 1960 Or thus , = -1580 9 280 ...
... EXAMPLES . 1. Add 74 , of , and 7 together . 15 First . 7 , of 3 , and 7-7 . Then the fractions are 39 , and ; therefore , 39x56x 1 = 2184 15X 5X 1 = 75 7x 5X56-1960 4219 3 ' 56 ' 5x56x1 = 280 2184 + 75 + 1960 Or thus , = -1580 9 280 ...
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Common terms and phrases
aliquot alloy angle annexed annuity annum answer assumed root Avoirdupois bushel carats circle common difference compound interest cube root cubick currency cyphers decimal denominator diameter ditto divide the product dividend divisor dollars Dominical Letter English Money Epact equal equation EXAMPLES extract fame farthings feet find the value firſt foot fourth fquare gain gallons geometrical given number given price given quantity gold Golden Number greatest term half inches last term latus rectum lefs length Livres Tournois logarithm miles mixed moidore months Multiply muſt New-Jersey New-York number of terms payment pence perpendicular pounds present worth principal PROBLEM proportion question quotient ratio Reduce remainder repetend right hand RULE RULE.-Multiply shillings side South-Carolina Spanish milled Dollars specifick gravity square root subtract Suppose Table THEOREM third triangle vulgar fraction weight whole numbers yards cost
Popular passages
Page 181 - RULE. •f- 1 . Separate the given number into periods of three figures each, by putting a point over the unit figure, and every third figure beyond the place of units. 2. Find the greatest cube in the left hand period, and put its root in the quotient. 3.
Page 183 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 245 - The present worth of any sum, due some time hence, is such a sum, as, if put to interest, would in that time, and at the rate per cent. for which the discount is to be made, amount to the sum or debt then due.
Page 175 - Distinguish the given number into periods of two figures each, by putting a point over the place of units, another over the place of hundreds, and so on, which points show the number of figures the root will consist of.
Page 61 - Divide by any number that will divide two or more of the given numbers without a remainder, and set the quotients, together with the undivided numbers, in a line beneath.
Page 134 - If 8 men can build a wall 20 feet long, 6 feet high and 4 feet thick, in 12 days ; in what time will 24 men build one 200 feet long, 8 feet high, and 6 feet thick ? 8 : 12 : : 20x6x4 24: 200x8x6 80 (lays, Jlns.
Page 175 - ... and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. " Place the double of the root, already found, on the lefl hand of the dividend for a divisor. 4. " Seek how often the divisor is contained...
Page 170 - Tret are practical rules for deducing certain allowances, •which are made by merchants and tradesmen in selling their goods by weight.
Page 79 - ... from the right hand of the quotient, point off so many places for decimals, as the decimal places in the dividend exceed those in the divisor.
Page 181 - Seek how often the divisor may be had in the dividend, and place the result in the quotient.