 Exercites. 1. If 14 horses eat 56 bushels of oats in 16 days, how many horses will 120 bushels keep for 24 days? 2. If a person walking 12 hours a day travel 250 miles in 9 days,. in how many days of 10 hours each could he walk 400 miles, at the same...  Rudiment: Treatise on Arithmetic, with Key - Page 109by J. R. Young - 1854Full view - About this book
 | Francis Walkingame - 1835 - 270 pages
...dividend ; the quotient of these will be the answer, in the same denomination as the third term. EXAMPLES. (1) If 14 horses eat 56 bushels of oats in 16 days, how many bushels will be sufficient for 20 horses 24 days? S Dividend x xM = ,0 x 3 x 4 J?' An,. Divisor W x... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...after the rate of 874 cents the square yard ; to what did it amount at that rate 1 Ans. $108,28 cts. 3. If 14 horses eat 56 bushels of oats in 16 days, how many bushels will be sufficient for 20 horses 24 days ? Ans. 120 bushels, 4. If 112 acres of grass can be... | |
 | Richard W. Green - Arithmetic - 1840 - 300 pages
...will last 7 men 14 days, how much will last 3 men 21 days ? Ans. Srrri = SJLFJl = Ans. 36 loaves. 2. If 14 horses eat 56 bushels of oats in 16 days, how many bushels will be sufficient to keep 20 horses 24 clays? Ans. 120 bushels. 3. If 40s. will pay 8 men... | |
 | Commissioners of National Education in Ireland - 1842 - 160 pages
...fourth proportional, several circumstances require to be considered, it is called Compound Proportion. If 14 horses eat 56 bushels of oats in 16 days ; how maiij bushels will be required for 20 horses for 24 days ? frttffA. RULE wiTHExAMPLE. — Write horses... | |
 | Alfred Crowquill - Arithmetic - 1843 - 156 pages
...for a divisor, and the other three for the dividend, and the quotient will be the answer. EXAMPLES. If 14 horses eat 56 bushels of oats in 16 days; how many bushels will be sufficient for 20 horses for 24 days ? By two single rules. .* Or, in one stating,... | |
 | P. Fletcher - Arithmetic - 1848 - 138 pages
...many as any question, however complex, may require, can be worked, and easily worked, by this rule. If 14 horses eat 56 bushels of oats in 16 days, how many bushels will be required for 20 horses for 24 days ? In the above question the pupil will observe there... | |
 | Ireland commissioners of nat. educ - 1850 - 160 pages
...fourth proportional, several circumstances require to be considered, it is called Compound Proportion. If 14 horses eat 56 bushels of oats in 16 days ; how many bushels will be required for 20 horses for 24 days? bush. RULE wiTHExAMPLE. — Write horses 14 : 20... | |
 | John Radford Young - Arithmetic - 1852 - 230 pages
...the fraction - : which, J 11x18 by striking out common factors, becomes simply 5x2 or 10. Exercites. 1. If 14 horses eat 56 bushels of oats in 16 days,...rate ? 3. If 12*. be paid for the carriage of 2 cwt. 3 qr. 192 miles, how much should be paid for the carriage of 8 cwt. 1 qr. 128 miles? 4. If 3000 copies... | |
 | J L. Ellenberger - 1854 - 338 pages
...weighed 14 ounces when wheat was 4s. per bushel, what must it weigh when wheat is 6s. 9d. per bushel ? 9. If 14 horses eat 56 bushels of oats in 16 days, how many bushels will serve 20 horses 24 days ? 10. What must be the breadth of a piece of ground which is 14$-... | |
 | John William Colenso (bp. of Natal.) - 1864 - 238 pages
...£28 ? 5. If 12 persons spend £160 in 4 months, how many will £853 6s. 8rf. last for 8 months ? 6. If 14 horses eat 56 bushels of oats in 16 days, how many might be kept on 120 bushels for 24 days? 7. If 3000 copies of a book of 1 1 sheets require 66 reams... | |
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