Practical and Mental Arithmetic: On a New Plan, in which Mental Arithmetic is Combined with the Use of the Slate ...Richardson, Lord and Holbrook, 1830 - Arithmetic |
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Page 21
... hence its introduction into our own country . Q. About what time was it introduced into England ? A. About the mid- dle of the eleventh century . Q. How extensively is it now used ? A. All over the civilized world . As you have probably ...
... hence its introduction into our own country . Q. About what time was it introduced into England ? A. About the mid- dle of the eleventh century . Q. How extensively is it now used ? A. All over the civilized world . As you have probably ...
Page 40
... hence the 5 must be placed in the tens ' place . 13140 days , Ans . To explain why you add the two products together . What does multiplying 365 by 6 give ? A. The number of days in 6 years . What does multiplying 365 by 3 tens give ? A ...
... hence the 5 must be placed in the tens ' place . 13140 days , Ans . To explain why you add the two products together . What does multiplying 365 by 6 give ? A. The number of days in 6 years . What does multiplying 365 by 3 tens give ? A ...
Page 41
... hence the value is increased 10 times . What effect would two ciphers have , or three ciphers , & c . ? A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 , & c ...
... hence the value is increased 10 times . What effect would two ciphers have , or three ciphers , & c . ? A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 , & c ...
Page 55
... hence , when the cents are less than 10 , they must occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
... hence , when the cents are less than 10 , they must occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
Page 77
... Hence , to divide by 5 , 301 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the same , and the quotient will be the answer . 29. In 132 yards how many rods ? In 4224 yards ? A. 792 rods ...
... Hence , to divide by 5 , 301 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the same , and the quotient will be the answer . 29. In 132 yards how many rods ? In 4224 yards ? A. 792 rods ...
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Common terms and phrases
50 cents acres amount answer apiece apples bbls broadcloth bushels bushels of rye called ciphers cloth cost common fraction compound interest contained cord feet cube root currency decimal places derive the following dimes divide dividend dollars equal example Exercises farthings federal money feet long feet wide following RULE foot gain gallons gals gills give greatest common divisor hence hogshead hundred illustrations we derive improper fraction least common denominator least common multiple leaves length lowest terms merchant bought miles mills mixed number molasses months multiplicand Multiply OPERATION oranges ounces payment pence pints pound present worth principal proceed proportion pupil pwts quarts rate per cent ratio Reduce remainder repetend Rufus shillings Slate sold solid feet solid inches square feet square rods square root subtract third term whole number write yards of cloth
Popular passages
Page 21 - Decedents," and to repeal said original sections, -and to repeal sections one (1), two (2), three (3), four (4), five (5), six (6), seven...
Page 245 - Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Page 199 - But if any payments be made before one year's interest hath accrued, then compute the interest on the principal sum due on the obligation for one year,* add it to the principal, and compute the interest on the sum paid from the time it was paid up to the end of the year; add it to the sum paid, and deduct that sum from the principal and interest added together.
Page 53 - TABLE. 10 Mills (m.) = 1 Cent . . ct. 10 Cents = 1 Dime . . d. 10 Dimes = 1 Dollar . $. 10 Dollars = 1 Eagle . E.
Page 173 - Bought 40 gallons of molasses, at 27 cents a gallon ; but, by accident, 4 gallons leaked out ; at what rate must I sell the remainder, per gallon, to lose nothing?
Page 242 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 76 - In 2 ? In 3 ? In 4? In 5? In 6? In 7? In 8? In 9? In 10? In 11 ? 5.
Page 255 - Two persons, A and B, have the same income: A saves |- of his yearly ; but B, by spending $150 per annum more than A, at the end of 8 years, finds himself $400 in*debt ; what is their income, and what does each spend per annum '? A.
Page 172 - B $200, to be paid in 6 months ; $300, in 12 months ; $500, in 3 months ; what is the equated time for the payment of the whole?
Page 197 - ... due: add that interest to the principal, and from the sum subtract the payment made at that time, together with the preceding payments (if any) and the remainder forms a new principal ; on which, compute and subtract the interest, as upon the first principal: and proceed in this manner to the time of the judgment.